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Olin [163]
3 years ago
10

The mean weight of nine players and three reserve players is 188 pounds.find the mean weight of the three reserve players

Mathematics
1 answer:
Katen [24]3 years ago
5 0

Answer:

83.56/p

Step-by-step explanation:

Let the weight of the players = p

Let the weight of the reserve players = r

Since there 9 players, there weight = 9p

And since there 3 reserve players, there weight = 3r

(9p + 3r) / 12 = 188

9p + 3r = 12 * 188

9p + 3r = 2256

Solve for r

r = 2256 / 27p

r = 83.56/p

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Zepler [3.9K]

Answer:

8

Step-by-step explanation:

So, $4x4weeks= 16

4x2=8

So he had 8 MORE money than in 4 weeks

4 0
2 years ago
Condense the following logs into a single log:
mamaluj [8]

QUESTION 1

The given logarithm is

8\log_g(x)+5\log_g(y)

We apply the power rule of logarithms; n\log_a(m)=\log_(m^n)

=\log_g(x^8)+\log_g(y^5)

We now apply the product rule of logarithm;

\log_a(m)+\log_a(n)=\log_a(mn)

=\log_g(x^8y^5)

QUESTION 2

The given logarithm is

8\log_5(x)+\frac{3}{4}\log_5(y)-5\log_5(z)

We apply the power rule of logarithm to get;

=\log_5(x^8)+\log_5(y^{\frac{3}{4}})-\log_5(z^5)

We apply the product to obtain;

=\log_5(x^8\times y^{\frac{3}{4}})-\log_5(z^5)

We apply the quotient rule; \log_a(m)-\log_a(n)=\log_a(\frac{m}{n} )

=\log_5(\frac{x^8\times y^{\frac{3}{4}}}{z^5})

=\log_5(\frac{x^8 \sqrt[4]{y^3} }{z^5})

7 0
2 years ago
Student
Bess [88]

Step-by-step explanation:

Is that the whole question or can you give me more information?

6 0
3 years ago
Water flows through a pipe at a rate of 490 milliliters every 6.5 hours. Express this rate of flow in fluid ounces per minute.
sergij07 [2.7K]

Answer:

0.42

Step-by-step explanation:

8 0
3 years ago
Patricia and Joe Payne are divorced. The divorce settlement stipulated that Joe pay $485 a month for their daughter Suzanne unti
zhuklara [117]
\bf \qquad \qquad \textit{Future Value of an ordinary annuity}
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\bf \begin{cases}
A=
\begin{array}{llll}
\textit{original amount}\\
\textit{already compounded}
\end{array} &
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &
\begin{array}{llll}
485\cdot 12\\
\underline{5280}
\end{array}\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{a year, thus once}
\end{array}\to &1\\

t=years\to &4
\end{cases}
\\\\\\


\bf A=5280\left[ \cfrac{\left( 1+\frac{0.06}{1} \right)^{1\cdot  4}-1}{\frac{0.06}{1}} \right]

Joe is making $485 payments monthly, but the amount gets interest on a yearly basis, not monthly, so the amount that yields interest is 485*12

also, keep in mind, we're assuming is compound interest, as opposed to simple interest
3 0
3 years ago
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