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Olin [163]
3 years ago
10

The mean weight of nine players and three reserve players is 188 pounds.find the mean weight of the three reserve players

Mathematics
1 answer:
Katen [24]3 years ago
5 0

Answer:

83.56/p

Step-by-step explanation:

Let the weight of the players = p

Let the weight of the reserve players = r

Since there 9 players, there weight = 9p

And since there 3 reserve players, there weight = 3r

(9p + 3r) / 12 = 188

9p + 3r = 12 * 188

9p + 3r = 2256

Solve for r

r = 2256 / 27p

r = 83.56/p

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I made 10 and three fifths gallons of soup of which 6 and one quarter gallons was chicken noodle. How much was not chicken noodl
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3 years ago
What is the average (arithmetic mean) of the first 90 measurements in a certain list of 92 measurements? (1) the average of the
marishachu [46]
The sum of all the measurements is just the average times the number.

\bar x = \frac{1}{n} \sum_{i=1}^n x_i

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That means the sum of the first 90 is 92 \times 7 - 2 \times 7.2

so the average of the first 90 is

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3 years ago
A four-person committee is chosen from a group of eight boys and six girls.
Alecsey [184]

Answer:

The answer is 10/143

Step-by-step explanation:

6 0
2 years ago
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