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geniusboy [140]
2 years ago
6

Identify ammonia. a. strong electrolyte, strong base b. weak electrolyte, strong base c. strong electrolyte, weak base d. nonele

ctrolyte e. weak electrolyte, weak base
Chemistry
1 answer:
dedylja [7]2 years ago
8 0

Answer:

Ammonia is a weak electrolyte, weak base.

Option e.

Explanation:

Ammonia can take a proton from water to make ammonium.

It is a base, because it takes proton.

When a compound can take protons, we know that is base, according to Bronsted Lowry theory.

We can't describe ammonia as a base, according to Arrhenius, but we know it is base according to Lewis, because the N from the ammonia can be a donor of its electron pair.

It is weak because an small amount of ammonia, can react to produce ammonium, between the protons of water. This is the equilibrium, where the ammonia is considered as the conjugate strong acid of ammonia.

NH₃ +  H₂O  ⇄  NH₄⁺  +  OH⁻     Kb

All the amines are considered as weak bases, because they look like ammonia, where the H of NH₃ are replaced by others chains.

------NH₂

-----NH-----

     

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Snezhnost [94]

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moles of Al₂(CO₃)₃ : = 0.147

<h3>Further explanation</h3>

Given

1. Reaction

C₅H₁₂+8O₂→6H₂O+5CO₂.

45.3 g water

2. 2AlCl₃ + 3MgCO₃ → Al₂(CO₃)₃ + 3MgCl₂

37.2 MgCO₃

Required

mass of pentane

moles of Al₂(CO₃)₃

Solution

1. mol water = 45.3 : 18 g/mol = 2.52

From equation, mol ratio of C₅H₁₂ : H₂O = 1 : 6, so mol pentane :

= 1/6 x mol H₂O

= 1/6 x 2.52

= 0.42

Mass pentane :

= mol x MW

= 0.42 x 72.15 g/mol

= 30.303 g

2. mol MgCO₃ : 37.2 : 84,3139 g/mol = 0.44

mol Al₂(CO₃)₃ :

= 1/3 x mol MgCO₃

= 1/3 x 0.44

= 0.147

4 0
2 years ago
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sukhopar [10]
<span>12810 atomic mass units
   Since a monomer is the basic building block of a polymer, we just need to multiply the mass of the monomers by the number of monomers used. So 105 atomic mass units * 122 = 12810 atomic mass units</span>
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When a cell is in a solution where the concentration of solute is the same in the cell as in the solution, the solution is calle
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Answer:

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Explanation:

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Hope I could help.

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