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Scorpion4ik [409]
3 years ago
14

begging u to answer Which is not an inter molecular force? Select one: a. Inter atomic bonds b. van der waals forces c. hydrogen

bonds
Chemistry
1 answer:
Elenna [48]3 years ago
6 0

Answer:

a-Interatomic bonds

Explanation:

First of all, it is not a force. Let alone be molecular force.

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A standard 10.00 g mass is weighed on an analytical balance 100 times. The average and standard deviation obtained gives 10.12 ±
Mekhanik [1.2K]

Answer:

There was an improvement in accuracy. There was no change in precision.

Explanation:

<em>The average mass after recalibration is closer to the mass of the standard, </em>so the recalibration improved the accuracy<em> </em>(the measurement is closer to an accepted 'true' value).

The standard deviation did not change, so the precision (or how disperse the measurements are) was not affected.

5 0
3 years ago
What air moves horizontally or parallel to the ground?
weqwewe [10]

Wind, air that moves to the ground

7 0
3 years ago
What determines the reactivity of a metal?
fgiga [73]
The reactivity of a metal is determined by how tightly the metal holds onto the electrons in the outermost energy levels (valence electrons)
7 0
3 years ago
In 0.4 mole of H2S, how many atoms of H are there? ​
Debora [2.8K]

Answer:

8

Explain

H: Ignoring the coefficient, we know there's 5+3=8 atoms

5 0
2 years ago
A sample of gas occupies 10.0 L at 240°C under a pressure of
NISA [10]

Answer: 1090°C

Explanation: According to combined gas laws

(P1 × V1) ÷ T1 = (P2 × V2) ÷ T2

where P1 = initial pressure of gas = 80.0 kPa

V1 = initial volume of gas = 10.0 L

T1 = initial temperature of gas = 240 °C = (240 + 273) K = 513 K

P2 = final pressure of gas = 107 kPa

V2 = final volume of gas = 20.0 L

T2 = final temperature of gas

Substituting the values,

(80.0 kPa × 10.0 L) ÷ (513 K) = (107 kPa × 20.0 L) ÷ T2

T2 = 513 K × (107 kPa ÷80.0 kPa) × (20.0 L ÷ 10.0 L)

T2 = 513 K × (1.3375) × (2)

T2 = 1372.275 K

T2 = (1372.275 - 273) °C

T2 = 1099 °C

8 0
3 years ago
Read 2 more answers
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