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Scorpion4ik [409]
4 years ago
14

begging u to answer Which is not an inter molecular force? Select one: a. Inter atomic bonds b. van der waals forces c. hydrogen

bonds
Chemistry
1 answer:
Elenna [48]4 years ago
6 0

Answer:

a-Interatomic bonds

Explanation:

First of all, it is not a force. Let alone be molecular force.

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Answer:

element -Lead

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Mass-207.2

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Mass-65.39

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What is This is a solid substance that is composed of minerals
Pani-rosa [81]

this is what i foudn-By its definition as a homogeneous solid, a mineral is composed of a single solid substance of uniform composition that cannot be physically separated into simpler chemical compounds. ... Most rocks are composed of several different minerals; e.g., granite consists of feldspar, quartz, mica, and amphibole.

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8 0
3 years ago
Calculate how many grams of hydrogen can be burned if 40. liters of oxygen at 200. k and 1.0 atm. show work pls.
Wittaler [7]

The grams of hydrogen gas can be burned if 40. liters of oxygen at 200. k and 1.0 atm is 4.88 grams.

<h3>How do we calculate grams from moles?</h3>

Grams (W) of any substance will be calculated by using their moles (n) through the following equation:

  • n = W/M, where

M = molar mass

And moles of the gas will be calculated by using the ideal gas equation as:

  • PV = nRT, where

P = pressure = 1atm

V = volume = 40L

n = moles = ?

R = universal gas constant = 0.082 L.atm / K.mol

T = temperature = 200K

On putting these values on the above equation, we get

n = (1)(40) / (0.082)(200) = 2.439 = 2.44 moles

  • Now grams of hydrogen gas will be calculated by using the first equation as:

W = (2.44mol)(2g/mol) = 4.88g

Hence required mass of hydrogen gas is 4.88g.

To know more about ideal gas equation, visit the below link:

brainly.com/question/15046679

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3 years ago
PLZ HELP For the reaction: 2NO2(g) → N2O4(l),
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Answer: \Delta H_{rxn}=-20kJ/mol-(+66kJ/mol)

Explanation:

Heat of reaction or enthalpy change is the energy released or absorbed during the course of the reaction.

It is calculated by subtracting the enthalpy of reactants from the enthalpy of products.

\Delta H=H_{products}-H_{reactants}

\Delta H = enthalpy change = ?

H_{products} = enthalpy of products

H_{reactants} = enthalpy of reactants

For the given reaction :

2NO_2(g)\rightarrow N_2O_4(l)

\Delta H=H_{N_2O_4}-2\times H_{NO_2}

\Delta H=-20kJ/mol-(+66kJ/mol)

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