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VladimirAG [237]
3 years ago
14

Which of the following describes a simple event?

Mathematics
2 answers:
nirvana33 [79]3 years ago
7 0
I think that it is B
maxonik [38]3 years ago
6 0
The answer is rolling a die
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A, C, E<br> A, C, D<br> B, D, E<br> C, D, E
Usimov [2.4K]

Answer: A C and E (1st choice)

Step-by-step explanation:

7 0
3 years ago
If a+b+c =0 show that a³+b³+c³= 3abc
slega [8]

Answer:

Step-by-step explanation:

a+b+c=0, a+b=-c,a+c=-b, b+c=-a

(a+b+c)^3=(a+b+c)^2*(a+b+c)=(a^2+b^2+c^2+2ab+2ac+2bc)*(a+b+c)=

a^3+ab^2+ac^2+2a^2b+2a^2c+2abc+a^2b+b^3+bc^2+2ab^2+2abc+2b^2c+a^2c+b^2c+c^3+2abc+2ac^2+2bc^2=a^3+b^3+c^3+3a^2b+3a^2c+3ac^2+3ab^2+3bc^2+3b^2c+6abc=

a^3+b^3+c^3+3a^2*(b+c)+3c^2(a+b)+3b^2(a+c)+6abc=

a^3+b^3+c^3+3a^2*(-a)+3c^2*(-c)+3b^2*(-b)+6abc=

a^3+b^3+c^3-3a^3-3c^3-3b^3+6abc=

6abc-2a^3-2b^3-2c^3=2(3abc-a^3-b^3-c^3)=

2*[3abc-(a^3+b^3+c^3)]=0

so 3abc-(a^3+b^3+c^3)=0

so a^3+b^3+c^3=3abc

7 0
3 years ago
Plz find the volume of this figure i really need help​
DiKsa [7]

Answer:

to find volume you have to multiply l x w x h

Step-by-step explanation:

just put the l, w, and height in the comment section so i can give you the answer

3 0
3 years ago
(5*10^-2)divide by (2*10^3)
DaniilM [7]

Answer:

2.5 × 10^-5

<em>please correct me if im wrong</em><em>.</em>

6 0
3 years ago
Calculate the value of A in the statement​
tigry1 [53]

please edit your question man

4 0
2 years ago
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