Answer:
The shaded area is ![23\ in^{2}](https://tex.z-dn.net/?f=23%5C%20in%5E%7B2%7D)
Step-by-step explanation:
we know that
The shaded area is equal to the area of the large square minus the area of the two smaller squares
so
![A=6^{2} -(3^{2} +2^{2})\\ \\ A=(2*3)^{2} -(3^{2} +2^{2})\\ \\A=(2^{2})(3^{2}) -(3^{2} +2^{2})](https://tex.z-dn.net/?f=A%3D6%5E%7B2%7D%20-%283%5E%7B2%7D%20%2B2%5E%7B2%7D%29%5C%5C%20%5C%5C%20A%3D%282%2A3%29%5E%7B2%7D%20-%283%5E%7B2%7D%20%2B2%5E%7B2%7D%29%5C%5C%20%5C%5CA%3D%282%5E%7B2%7D%29%283%5E%7B2%7D%29%20-%283%5E%7B2%7D%20%2B2%5E%7B2%7D%29)
Calculate the shaded area
Remember that
![3^{2}=9\\ 2^{2}=4](https://tex.z-dn.net/?f=3%5E%7B2%7D%3D9%5C%5C%202%5E%7B2%7D%3D4)
substitute
![A=(4)(9) -(9 +4)\\ \\A=36-13\\ \\A=23\ in^{2}](https://tex.z-dn.net/?f=A%3D%284%29%289%29%20-%289%20%2B4%29%5C%5C%20%5C%5CA%3D36-13%5C%5C%20%5C%5CA%3D23%5C%20in%5E%7B2%7D)
Answer:
<h2>A. 2x² + 5x + 1</h2>
Step-by-step explanation:
![7x^2-6+4x+7-5x^2+x\qquad\text{combine like terms}\\\\=(7x^2-5x^2)+(4x+x)+(-6+7)\\\\=2x^2+5x+1](https://tex.z-dn.net/?f=7x%5E2-6%2B4x%2B7-5x%5E2%2Bx%5Cqquad%5Ctext%7Bcombine%20like%20terms%7D%5C%5C%5C%5C%3D%287x%5E2-5x%5E2%29%2B%284x%2Bx%29%2B%28-6%2B7%29%5C%5C%5C%5C%3D2x%5E2%2B5x%2B1)
Answer:
![x\geq -\frac{15}{2}](https://tex.z-dn.net/?f=x%5Cgeq%20-%5Cfrac%7B15%7D%7B2%7D)
Step-by-step explanation:
add 4 on both sides
leaves you with 15 on the right side
you then divide by negative 2
since you divide by a negative you have to switch the sign
Answer:
3
Step-by-step explanation:
The natural log is the inverse of the exponential (and vise versa), so ln(e^3) = 3.
(This is the also same as e^(ln3))