Answer with explanation:
→y²+5y+6
=y²+3 y+2 y+6
=y×(y+3)+2×(y+3)
=(y+2)(y+3)
→y² -3 y-10
=y² -5 y+2 y -10
=y×(y-5)+2×(y-5)
=(y+2)(y-5)
Solve this inequality: 3q + 11 + 8q > 99.
2 answers:
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Answer with explanation:
→y²+5y+6
=y²+3 y+2 y+6
=y×(y+3)+2×(y+3)
=(y+2)(y+3)
→y² -3 y-10
=y² -5 y+2 y -10
=y×(y-5)+2×(y-5)
=(y+2)(y-5)