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2 years ago

What is the slope of the line passing through the points (2,-5) and(4,1)

1 answer:

6 0

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-5)}{4-2}\implies \cfrac{1+5}{2}\implies \cfrac{6}{2}\implies 3$

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Find the slope of the line shown.

kumpel [21]

Add the pic and I’ll be able to answer it

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3 years ago

How to solve all the questions in the pictures please

IgorLugansk [536]

Answer:

See attachments

Step-by-step explanation:

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2 years ago

Rachel is saving money to buy a bike. She has $52 and is going to save an additional $8 each week. The bike costs $164. In how m

Mama L [17]

Answer: She will have to save for 8 weeks.

Step-by-step explanation:

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3 years ago

Select the correct answer. Given the following formula, solve for a. A. B. C. D. s=a+b+C/2

nexus9112 [7]

Hey there!

The answer to your question is a = s - b - C/2

To solve for "a", we must get "a" on it's own side of the equal sign. We can first subtract "s" from both sides:

0 = a + b + C/2 - s

Then, we can subtract a from both sides:

-a = b + C/2 - s

Finally, we divide both sides by -1, so a is by itself.

a = -b - C/2 + s

And we can rearrange it to the standard form:

a = s - b - C/2

Good luck, and hope it helped! Have a great day!

7 0

2 years ago

The amount of saturated fat in a daily serving of a particular brand of breakfast cereal is normally distributed with mean 25 g

Soloha48 [4]

Answer:

a) $\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And replacing we got:

$\bar X \sim N(\mu=25, \frac{4}{\sqrt{30}}= 0.730)$

b) $z =\frac{27-25}{\frac{4}{\sqrt{30}}}= 2.739$

And using the normal standard distribution table and the complement rule we got:

$P(z>2.739) =1- P(z$

Step-by-step explanation:

From the info given if we define the random variable X as "amount of saturated fat in a daily serving of a particular brand of breakfast cereal " we know that the distribution of X is given by:

$X \sim N(\mu =25, \sigma =4)$

Part a

For this case the sample size would be n =30 and then the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And replacing we got:

$\bar X \sim N(\mu=25, \frac{4}{\sqrt{30}}= 0.730)$

Part b

We want to find this probability:

$P(\bar X >27)$

And we can use the z score formula given by:

$z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z =\frac{27-25}{\frac{4}{\sqrt{30}}}= 2.739$

And using the normal standard distribution table and the complement rule we got:

$P(z>2.739) =1- P(z$

3 0

2 years ago