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3 years ago

3.72 plus 6.0064 (this is just part of my question.)

Mathematics

2 answers:

tino4ka555 [31]3 years ago

6 0

The answer is 9.7546

Bond [772]3 years ago

4 0

Answer:

9.7264

Step-by-step explanation:

3.72 + 6.0064 = 9.7264

I hope this helps!

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Need help plzz I am struggling

otez555 [7]

The equation you need to find x is,

$12x^{\circ}+30^{\circ}=90$ .

Then solving for x gives you $x=5$ .

Hope this helps.

7 0

3 years ago

If X and Y are independent continuous positive random

Leni [432]

a) $Z=\frac XY$ has CDF

$F_Z(z)=P(Z\le z)=P(X\le Yz)=\displaystyle\int_{\mathrm{supp}(Y)}P(X\le yz\mid Y=y)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}P(X\le yz)P(Y=y)\,\mathrm dy$

where the last equality follows from independence of $X,Y$ . In terms of the distribution and density functions of $X,Y$ , this is

$F_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy$

Then the density is obtained by differentiating with respect to $z$ ,

$f_Z(z)=\displaystyle\frac{\mathrm d}{\mathrm dz}\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy=\int_{\mathrm{supp}(Y)}yf_X(yz)f_Y(y)\,\mathrm dy$

b) $Z=XY$ can be computed in the same way; it has CDF

$F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}F_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Differentiating gives the associated PDF,

$f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Assuming $X\sim\mathrm{Exp}(\lambda_x)$ and $Y\sim\mathrm{Exp}(\lambda_y)$ , we have

$f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}$

and

$f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy$

I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.

6 0

3 years ago

Can someone pls help me with this

Over [174]

i believe it is 2 i took the test but it was a while ago sorry if it’s wrong!

4 0

3 years ago

What will happenif you: multiply one charge by 2.0, multiply the other charge by 4.8, and multiply the distance between them by

noname [10]

Yes it is.
F1 = k q1 * q2 / r^2
F2 = k *(2*q1) * (4.8 q2) / (7.2 r^2)

Work on F2 for a moment.
F2 = k * 9.6 (q1*q2) / 51.84
F2 = (9.6/ 51.84) * k * q1 * q2 / r^2
Since k * q1 * q2/r^2 is the same in both questions let kq1*q2/r^2 = m

F1 = m
F2 = 0.18 m

So to make it easier F2/F1 = 0.18m / m
F2/ F1 = 0.18 the m's cancel.

And that should be how you do the question.

4 0

3 years ago

What value of x satisfies the equation x2 34=74?

IrinaVladis [17]

X^2+34=74
minus 34 from both sides
x^2=40
sqrt both sides
x=+/-√40
x=+/-2√10

the values 2√10 and -2√10 are soltuions for x

3 0

3 years ago