Yuck, trig. I'm doing college trig at this very moment.
the top half (1+(2sinθ)cosθ)=1+sin(2θ)
because 2sinθcosθ=sin(2θ) is an identity
Using polynomial division your answer becomes:
(csc θ)(sec θ)+2
Answer:
There are 36 possibilities per character (26 lower case letters + 10 numbers), so the total number of permutations are 36^4 = 1,679,616
Step-by-step explanation:
Let log5 125 = x
Removing log you get 5^x = 125
Rewrite 125 as 5^3
Now 5^x = 5^3
x = 3
<span>A peer-viewed article. </span>
Answer:
D) no solution
Step-by-step explanation:
1/ (x-2) + 1/(x+2) = 4/(x^2-4)
x cannot equal 2 or -2 since that would make our fractions equal 1/0 or be undefined
Factor the term on the right
1/ (x-2) + 1/(x+2) = 4/(x-2)(x+2)
Multiply both sides by (x-2) (x+2)
(x-2) (x+2) (1/ (x-2) + 1/(x+2)) = 4/(x-2)(x+2)*(x-2) (x+2)
Distribute
x+2 + (x-2) = 4
Combine like terms
2x = 4
Divide by 2
2x/2 = 4/2
x =2
But this is not a possible solution since that is not in the domain
