Ask question

Ask question

All categories

3 years ago

7

Mr. Rodriguez bought a supply of 20 Reams of printer paper. Each Ream Contains 500 sheets of paper. How many sheets of printer p

aper are there?

2 answers:

Umnica [9.8K]3 years ago

4 0

Multiply its 10'000 I hope this helps

KonstantinChe [14]3 years ago

3 0

500 times 20 is the equation
the answer is 1,000<span />

You might be interested in

What causes a graph to move vertically?

docker41 [41]

The vertical shifts in graphs are caused by a constant added to the output (y - axis).

<h3>What is vertical shift in a graph?</h3>

Vertical shifts are outside changes that affect the output (y- axis) values and shift the function up or down (vertical direction).

Horizontal shifts are inside changes that affect the input (x-) axis values and shift the function left or right

<h3>The cause of vertical shift in a graph</h3>

The vertical shift results from a constant added to the output (y - axis). The graph will move up if the constant added is positive OR it will move down if the constant is negative.

Thus, the vertical shifts in graphs are caused by a constant added to the output (y - axis).

Learn more about vertical shifts in graph here: brainly.com/question/27653529

#SPJ1

8 0

1 year ago

Which sign makes the statement true?<br> 590 ? 5 × 10^2<br> (>) (<) (=)

ludmilkaskok [199]

Answer:

>

Step-by-step explanation:

5 × 10^2 = 500

so 590 is greater than or > 5 × 10^2 or 500

3 0

3 years ago

Determine the area enclosed by y=2x+3, the x-axis and the ordinates x=3 and x=4

jok3333 [9.3K]

Answer:

$\displaystyle \int\limits^4_3 {2x + 3} \, dx = 10$

General Formulas and Concepts:
<u>Calculus</u>

Integration

Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

y = 2x + 3

<em>x</em>-interval [3, 4]

<em>x</em>-axis

<em>See attachment for graph.</em>

<u>Step 2: Find Area</u>

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^4_3 {2x + 3} \, dx$
[Integral] Rewrite [Integration Property - Addition/Subtraction]: $\displaystyle A = \int\limits^4_3 {2x} \, dx + \int\limits^4_3 {3} \, dx$
[Integrals] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 2 \int\limits^4_3 {x} \, dx + 3 \int\limits^4_3 {} \, dx$
[Integrals] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = 2 \bigg( \frac{x^2}{2} \bigg) \bigg| \limits^4_3 + 3(x) \bigg| \limits^4_3$
[Integrals] Integrate [Integration Rule - FTC 1]: $\displaystyle A = 2 \bigg( \frac{7}{2} \bigg) + 3(1)$
Simplify: $\displaystyle A = 10$

∴ the area bounded by the region y = 2x + 3, x-axis, and the coordinates x = 3 and x = 4 is equal to 10.

---

Learn more about integration: brainly.com/question/26401241

Learn more about calculus: brainly.com/question/20197752

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

3 0

2 years ago

I need the answer now please

xxMikexx [17]

Answer:

180/147

Step-by-step explanation:

We need to find the additive inverse of the given numbers.

For finding it we may simply out -1 as multiplication in front of the terms .

<u>SOLUTION</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u>

→ 3/-7 - 11/21

→ -3/7 -11/21

→ 3×-3 - 11 /21

→ -9-11/21

→ -20/21

<u>SOLUTION</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

→ 9/5 ÷ 7/5

→ 9/5 × 5/7

→ 9/7

→ Product of nos . = -20/21 × -9/7

→ Ans = 180/147

7 0

3 years ago

.MARY WAS TOLD TO RUN AROUND THE TRACK 5 TIMES BY HER COACH. ONCE AROUND THE TRACK IS 5/6 OF A MILE. MARY WAS ONLY ABLE TO RUN A

Alenkasestr [34]

Answer:

3.61 miles

Step-by-step explanation:

Given that:

Length of track = 5/6 of a mile

Number times Mary was able to run around the track = 4 1/3 times

Total miles ran by Mary :

(Equivalent mile of the track * number of times Mary ran around the track)

5/6 of a mile * 4 1/3 times

5/6 * 13/3

= 65 / 18

= 3.611111 miles

Hence, total Number of miles ran by Mary is 3.61 miles

3 0

3 years ago