Answer:
(a) The angle of projection is 63 degree.
(b) The velocity of projection is 24.5 m/s.
Explanation:
Height, h = 1 m
horizontal distance, d = 50 m
time, t = 4.5 s
Let the initial velocity is u and the angle is A.
(a) Horizontal distance = horizontal velocity x time
50 = u cos A x 4.5
u cos A = 11.1 .....(1)
Use second equation of motion in vertical direction
Divide (2) by (1)
tan A = 1.97
A = 63 degree
(b) Substitute the value of A in equation (2)
u x sin 63 = 21.8
u = 24.5 m/s
Answer:
The magnitude of the net electric field inside the solution is 3.704 N/C
Explanation:
Given;
average drift speed, v = 3 x 10⁻⁷ m/s
mobility of the bromide ions, μ = 8.1 x 10⁻⁸ (m/s)(N/C)
The magnitude of the net electric field inside the solution is given by the equation below;
where;
E is the magnitude of the net electric field inside the solution
Substitute the given values and solve for E
Therefore, the magnitude of the net electric field inside the solution is 3.704 N/C
Answer:
a) 4.681*10^10 electrons
b) 3.67*10^12 electrons
Explanation:
The amount of electrons in a charge of 1C is:
You use the previous equality as a conversion factor.
a) The sing of the charge is not important in the calculation of the number electrons, so, you use the absolute value of the charge
In 7.50nC there are 4.61*10^18 electrons
b)
To obtain a charge of 0.580 µC in a neutral object you need to take out 3.67*10^12 electrons