All categories

3 years ago

Which of the following figures has a length, width, and height?

Mathematics

2 answers:

Ipatiy [6.2K]3 years ago

8 0

Answer:

Pyramid

Step-by-step explanation:

Square is flat so no height.

Line segment is a flat line so no height

point is a literal dot

pyramid is a 3d figure so it would ahve all of the attributes

rodikova [14]3 years ago

5 0

Answer:

I believe

D. Pyramid

Is the answer I did it in 6th or 7th grade

Step-by-step explanation:

Square is flat so no height.

Line segment is a flat line so no height

point is a literal dot

pyramid is a 3d figure so it would have all of the attributes

We both helped right?

You might be interested in

THIS I SUPPOSED TO BE EASY BUT I CANT GET IT GIVING BRAINLETS

arsen [322]

Answer:

Step-by-step explanation:

2/10=.2, 6.2

6.2×6=37.2

37.2+6.2= 43.4

43.4= 43 $\frac{4}{10}$

3 0

3 years ago

Central therom in statistics

aev [14]

Answer:

whats the question

Step-by-step explanation:

4 0

4 years ago

Please help what does B and C equal

lapo4ka [179]

Answer:

m∠b=20°

m∠c=160°

Step-by-step explanation:

∠c and the 160° angle are vertical, so they are congruent.

m∠c=160°

∠c and ∠b are supplementary, so their sum is 180°.

$b+160=180$

$b=20$

So, m∠b=20°.

8 0

3 years ago

In the diagram, AD=CD=CB and measure of angle A=40°. How many degrees are in angle DCB?

Ad libitum [116K]

Answer:

$20^{\circ}$

Step-by-step explanation:

Consider triangle ACD. This triangle is isosceles triangle, because AD = DC. Angles adjacent to the base AC are congruent abgles, so

$m\angle DAC=m\angle DCA=40^{\circ}$

The sum of the measures of all interiror angles in the triangle is always $180^{\circ},$ then

$m\angle DAC+m\angle DCA+m\angle ADC=180^{\circ}\\ \\40^{\circ}+40^{\circ}+m\angle ADC=180^{\circ}\\ \\m\angle ADC=180^{\circ}-40^{\circ}-40^{\circ}=100^{\circ}$

Angles ADC and BDC are supplementary angles (add up to $180^{\circ}$ ), then

$m\angle BDC=180^{\circ}-100^{\circ}=80^{\circ}$

Consider triangle BCD. This triangle is isosceles triangle because BC = DC. Angles adjacent to the base BD are congruent abgles, so

$m\angle BDC=m\angle DBC=80^{\circ}$

The sum of the measures of all interiror angles in the triangle is always $180^{\circ},$ then

$m\angle DBC+m\angle BDC+m\angle BCD=180^{\circ}\\ \\80^{\circ}+80^{\circ}+m\angle BCD=180^{\circ}\\ \\m\angle BCD=180^{\circ}-80^{\circ}-80^{\circ}=20^{\circ}$

6 0

3 years ago

Please help with question 5!! BRAINLIEST to correct answer!

REY [17]

I’d go with A

kabiwbhej

3 0

3 years ago