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Anna71 [15]
3 years ago
7

Complete the square for each expression. Then factor the Trinomial x^2+8x

Mathematics
1 answer:
Goryan [66]3 years ago
8 0

The value of x is x=0 or x=-8

Step-by-step explanation:

The expression is x^{2} +8x=0

To complete the square, the equation is of the form ax^{2} +bx+c=0

The constant term c can be determined using, c=\left(\frac{\frac{b}{a}}{2}\right)^{2}

\begin{aligned}c &=\left(\frac{8}{2}\right)^{2} \\&=\left(\frac{8}{2}\right)^{2} \\c &=4^{2} \\c &=16\end{aligned}

Rewriting the expression x^{2} +8x=0 and factoring the trinomial, we have,

\begin{array}{r}{x^{2}+8 x+16=16} \\{(x+4)^{2}=16}\end{array}

Taking square root on both sides, we get,

\begin{aligned}&x+4=\sqrt{16}\\&x+4=\pm 4\end{aligned}

Either,

\begin{array}{r}{x+4=4} \\{x=0}\end{array}  or \begin{array}{r}{x+4=-4} \\{x=-8}\end{array}

Thus, the value of x is  x=0 or x=-8

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