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3 years ago

11

ΔABC is reflected across the x-axis and then translated 4 units up to create ΔA′B′C′. What are the coordinates of the vertices o

f ΔA′B′C′ ?

1 answer:

Vera_Pavlovna [14]3 years ago

3 0

Answer:

A) (-3, 3) B) (-1, 1) C) (-2, 3)

Step-by-step explanation:

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Kelly earns $23.00 for 4 hours of work. At that rate, how long would she have to work to earn $57.50?

ankoles [38]

Answer:

10 hours

Step-by-step explanation:

5.75x 10= 57.50

8 0

3 years ago

The center of a hyperbola is (−4,3) , and one vertex is (−4,7) . The slope of one of the asymptotes is 2.

Monica [59]

Answer:

The answer to your question is below

Step-by-step explanation:

C (-4, 3)

V (-4, 7)

asymptotes = 2 = $\frac{b}{a}$

- This is a vertical hyperbola, the equation is

$\frac{(y - k)^{2} }{a^{2} } + \frac{(x - h)^{2} }{b^{2} } = 1$

slope = 2

a is the distance from the center to the vertex = 4

b = 2(4) = 8

$\frac{(y - 3)^{2} }{4^{2} } + \frac{(x + 4)^{2} }{8^{2} } = 1$

$\frac{(y - 3)^{2} }{16} + \frac{(x + 4)^{2} }{64} = 1$

7 0

3 years ago

Read 2 more answers

What is the equation of the line with an x-intercept of -1 and a y-intercept of 2?

iragen [17]

Answer:

y = 2x + 2

Step-by-step explanation:

The general form

is;

y = mx + b

where m is the slope and b is the y-intercept

so we have;

y = mx + 2

To get m, substitute the point (-1,0)

So we have

0 = -m + 2

m = 2

So the equation is;

y = 2x + 2

4 0

3 years ago

A produce supplier ships boxes of produce to individual customers. The distribution of weights of shipped boxes is approximately

schepotkina [342]

Answer:

$0.67(4)+ 36$

Option D

Step-by-step explanation:

Given that a producer ships boxes of produce to individual customers.(say x)

X is a normal random variable with mean = 36 and std dev =4 lbs

By definition of std normal variate we know that

$\frac{x-36}{4}$ is N(0,1)

75th percentile of std normal distribution is

0.675

Hence corresponding x would be

$36+0.675(4)$

Option D matches with this value

Hence answer is option D

$0.67(4)+ 36$

5 0

3 years ago

Read 2 more answers

In ΔABC, if m ∠A = m∠C, m∠B = ß (where ß is an acute angle), and BC = x, which expression gives the length of b, the side opposi

chubhunter [2.5K]

Answer:

The length of b is $\sqrt{2x^2(1-cos\beta)}$ .

Step by step explanation:

Given information: In ΔABC, ∠A =∠C, ∠B = ß (where ß is an acute angle), and BC = x.

Since two angles are same therefore triangle ABC is an isosceles triangle and side AB and BC are congruent.

$AB=BC=x$

According to Law of cosine

$b^2=a^2+c^2-2ac\cos B$

$b^2=x^2+x^2-2(x)(x)\cos \beta$

$b^2=2x^2-2x^2\cos \beta$

$b^2=2x^2(1-\cos \beta)$

$\sqrt{2x^2(1-cos\beta)}$

Therefore the length of b is $\sqrt{2x^2(1-cos\beta)}$ .

6 0

3 years ago