Answer:
0.0562
Explanation:
Ph=-log[H+]
to find the h+ is the antilogarithm of the Ph.
Which is 10 raised to the power - Ph.
The generic equation for a reaction between an acid and water is
When an acid "reacts" with water, water acts as the base that accepts the proton (H+) from the acid. The remaining ion that is formed after the acid has donated its proton is called the conjugate base (
), and the conjugate acid-base pair is
-
.
Hydrogen sulfate (
) is an ion from sulfuric acid. It is still an acid in itself and can "react" with water ((
) to form the sulfate (
) and hydronium (
)ions.
Based on the previous discussion,
is identified to be the conjugate of the acid
.
Thus, the conjugate acid-base pair is 
.
Answer:
1.These results are accurate because the collected data is very close to the actual value.
4.These results are precise because all three trials are within a very close range.
Explanation:
Although in the ordinary language the terms precision and accuracy may be confused, in science those terms refer different properties of the measurements.
The accuracy is how close a measurement is to the true value, while the the precision refers to the reproducibility and repeatability, this is how the results show the same (close) value.
To differentiate precision and accuracy, It is very illustrative, to use the image of a throwing arrows to a target: if the arrows get close to the center of the target, then the results are accurate (close to the goal). If the arrows are not close to the cener of the target, but they are all close to each other, then the result is precise (the arrows land, approximately, in the same spot every time).
Answer:
0.95 L
Explanation:
Step 1: Given data
Concentration of the Mg(NO₃)₂ solution (C): 0.32 M (0.32 mol/L)
Mass of Mg(NO₃)₂ (solute): 45 g
Step 2: Calculate the moles corresponding to 45 g of Mg(NO₃)₂
The molar mass of Mg(NO₃)₂ is 148.33 g/mol.
45 g Mg(NO₃)₂ × 1 mol Mg(NO₃)₂ /148.33 g Mg(NO₃)₂ = 0.303 mol Mg(NO₃)₂
Step 3: Calculate the volume of solution that contains 0.303 moles of Mg(NO₃)₂
The concentration of the solution is 0.32 M, that is, there are 0.32 moles of Mg(NO₃)₂ per liter of solution.
0.303 mol Mg(NO₃)₂ × 1 L Solution / 0.32 mol Mg(NO₃)₂ = 0.95 L
Answer:
The metallic character increases as you go down a group. Since the ionization energy decreases going down a group (or increases going up a group), the increased ability for metals lower in a group to lose electrons makes them more reactive.
Explanation:
