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Lubov Fominskaja [6]
3 years ago
15

Calculate the approximate number of molecules in a drop of water with a mass of 0.10 g.

Chemistry
2 answers:
OLEGan [10]3 years ago
6 0

Answer:

Option A. 3 × 10^21 molecules

Explanation:

From Avogadro's hypothesis, 1mole of any substance contains 6.02x10^23 molecules. This means that 1mole of H20 also contains 6.02x10^23 molecules.

1mole of H2O = (2x1) + 16 = 2 + 16 = 18g

If 1mole(i.e 18g) of H2O contains 6.02x10^23 molecules,

Therefore 0.1g of H2O will contain = (0.1 x 6.02x10^23) /18 = 3 x 10^21 molecules

AlladinOne [14]3 years ago
5 0

Answer:

your answer is D -_- bc they want the approximate

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HELP PLEASE!!
AleksandrR [38]

Answer:

The mass of the object would be 491.55g/mL. Hope this helped! :)

Explanation:

D= 7.25g/mL                                                           M=D•V

V= 67.8mL

M=7.25g/mL•67.8mL

M= 491.55g

8 0
4 years ago
Consider the reaction represented by the equation?2SO2(g) + O2(g) 2SO3(g).?For the system at chemical equilibrium, which of the
rewona [7]

Answer:

b. The amount of SO3(g) decreases and the value for K increases.

Explanation:

Hello,

In this case, for the given reaction:

2SO_2(g) + O_2(g)\rightleftharpoons  2SO_3(g)

The change in the stoichiometric coefficient is:

\Delta \nu=2-2-1=-1

In such a way, since the reagents have more moles than the products, based on Le Chatelier's principle, if the volume is increased, the side with more moles is favored. In addition, since the formation of reagent is favored, K is diminished based on the law of mass action shown below:

K=\frac{[SO_3]_{eq}^2}{[SO_2]_{eq}^2[O_2]_{eq}}

Therefore the answer is:

b. The amount of SO3(g) decreases and the value for K increases.

Best regards.

3 0
4 years ago
The ksp of zinc carbonate (znco3 is 1.0 × 10–10. what is the solubility concentration of carbonate ions in a saturated solution
Trava [24]
Ksp - solubility product constant is equivalent to equilibrium constant, except this constant is used to determine the solubility of ions of a solid in a solution. 
ksp is the product of the soluble ions in the compound. Higher the ksp value, higher the degree of solubility.
ZnCO₃ (s) ---> Zn²⁺ (aq) +  CO₃²⁻ (aq)
                         n            n
ksp = [Zn²⁺][CO₃²⁻]
In the equation equal amounts of ions Zn²⁺ and CO₃²⁻ ions are soluble. 
amount of ions soluble = n
ksp is therefore equal to;
ksp = n x n
ksp = n²
ksp = 1 * 10⁻¹⁰ M
therefore 
1 * 10⁻¹⁰ M = n²
n = 1 x 10⁻⁵ M
therefore concentration of CO₃²⁻ = 1 x 10⁻⁵ M
7 0
4 years ago
Read 2 more answers
2) Gas in a balloon occupies 3.3 L. What volume will it occupy if the pressure
miskamm [114]

Answer:

<h2>The answer is 3.7 L</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{3.3 \times 100000}{90000}  =  \frac{330000}{9000 }  \\  = 3.666666...

We have the final answer as

<h3>3.7 L</h3>

Hope this helps you

6 0
3 years ago
Some chemical reactants are listed in the table below. Complete the table by filling in the oxidation state of the highlighted a
Fantom [35]

Answer:

1. Cu = +2

2. O = – 2

3. C = +2

4. N = 0

Explanation:

Note:

A. The oxidation state of oxygen is always – 2 except in peroxides where it is – 1.

B. The oxidation state of Hydrogen is always +1 except in metallic hydrides where it is – 1.

Now let us solve the question given above.

1. CuO = 0 (ground state)

Cu + O = 0

O = – 2

Cu + (– 2) = 0

Cu – 2 = 0

Collect like terms

Cu = 0 + 2

Cu = +2

2. H2O = 0 (ground state)

2H + O = 0

H = +1

2(1) + O = 0

2 + O = 0

Collect like terms

O = 0 – 2

O = – 2

3. CO = 0 (ground state)

C + O = 0

O = – 2

C + (– 2) = 0

C – 2 = 0

Collect like terms

C = 0 + 2

C = +2

4. N2 = 0 (ground state)

2N = 0

Divide both side by 2

N = 0/2

N = 0

6 0
4 years ago
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