Answer:
1 mole CO2 = 44g i.e.by the complete combustion of 12g of carbon, 44g of CO2 is produced.
Explanation:
Answer:
6.45 joules
Explanation:
energy=10×(55-50)×0.129
=1.29×5
=6.45 J
hope this helps
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The good ozone protects us from the UV/ harmful radiations whereas bad ozone is an air pollutant.
Explanation:
- There are two types of ozone layer found in the earth's atmosphere extending from troposphere to stratosphere. They are good ozone and bad ozone.
- Bad ozone as mentioned earlier it is an air pollutant and found in the ground level of earth, most accurately the troposphere. Bad ozone is formed in the ground level of earth's atmosphere by the reaction between nitrogen oxides and organic compounds which are volatile
- The Good ozone is found in the stratosphere layer of the earth's atmosphere. They protect us from harmful radiations. Good ozone layer in the stratosphere of the atmosphere is being destroyed by hydrocarbons, CFCs, and human intervention
Answer:
What I came up with was D equaling out to be 42
Explanation:
Im assuming you just do the math
A. 3.5 x 104 = 364
B. 2.4 x 103 = 247.2
C. 1.4 x 10^2_2 = 280
D. 4.9 x 10-7 = 42
I hope I helped.
The amount of sugar is 2621 mg
Why?
The complete question is:
A 12.630 g milk chocolate bar is found to contain 8.315 g of sugar.
Part B. What will be the amount of sugar in milligrams if the size of the milk chocolate bar is reduced from 12.630 g to 4.000 g ?
To find the answer we have to determine first the amount of sugar in milligrams per gram of chocolate bar. We can find that by applying the following conversion factor:
Now, we have to determine the amount of sugar in milligrams if we had a chocolate bar with 4.000 g:
Have a nice day!
