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Snezhnost [94]
2 years ago
5

How many oxygen molecules are needed to make 10 carbon dioxide molecules according to the following balanced chemical equation?

2 CO + O2 → 2 CO2
Chemistry
1 answer:
11Alexandr11 [23.1K]2 years ago
6 0
<h2 /><h2 /><h2>answer.</h2>

five oxygen molecules

step by step explanation.

according to the equation,one molecule of oxygen is enough to react with two carbon molecules thus 10 carbon molecules need 5oxygen molecules

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Density is defined by the above term
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What is the percent composition of H in <br> C<br> 10<br> H<br> 20<br> ?
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7 0
2 years ago
Which of the following is not equal to 485 L?
ELEN [110]

Answer:

4.85 * 10^4\ mL

Explanation:

Given

485 L

Required

Determine the measurement not equal to 485L

0.485\ kL

<em>From standard unit of conversion;</em>

1 KL = 1000 L

<em>Multiply both sides by 485</em>

485 * 1 KL = 485 * 1000 L

485KL = 485000L

<em>Divide both sides by 1000</em>

\frac{485KL}{1000} = \frac{485000L}{1000}

0.485KL = 485L  ---- This is equivalent

---------------------------------------------------------------------------------------------

4.85 * 10^4\ mL

<em>From standard unit of conversion;</em>

1000 mL = 1 L

<em>Multiply both sides by 485</em>

485 * 1000 mL = 1 L * 485

485000\ mL = 485\ L

Convert to standard form

4.85 * 10^5\ mL = 485\ L

Hence; 4.85 * 10^4\ mL is not equivalent to 485L

---------------------------------------------------------------------------------------------

48500 \ cL

<em>From standard unit of conversion;</em>

100 cL = 1 L

<em>Multiply both sides by 485</em>

485 * 100 cL = 1 L * 485

48500\ cL = 485\ L

Convert to standard form

4.85 * 10^4\ cL = 485\ L ---- This is equivalent

---------------------------------------------------------------------------------------------

4.85 * 10^8 \ μL

<em>From standard unit of conversion;</em>

1000000 μL = 1 L

<em>Multiply both sides by 485</em>

485 * 1000000uL  = 1 L * 485

485000000uL = 485\ L

Convert to standard form

4.85 * 10^8\ uL = 485\ L ---- This is equivalent

From the list of given options;

4.85 * 10^4\ mL is not equivalent to 485L

4 0
3 years ago
PLEASE HELP 50 POINTS
stepladder [879]
It’s c add the side
4 0
2 years ago
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What mass of oxalic acid dihydrate, H2C2O4•2H2O, is needed to make a 0.357 M solution of oxalic acid in a 250.0mL volumetric fla
GalinKa [24]

Molarity is expressed as the number of moles of solute per volume of the solution. The mass of oxalic acid dihydrate needed for the solution is calculated as follows:

Amount in moles: (0.357 mol H2C2O4•2H2O / L) (.250 L ) = 0.0893 mol H2C2O4•2H2O


Amount in mass : 0.0893 mol H2C2O4•2H2O (126.08 g / mol ) = 11.2589 g H2C2O4•2H2O


Hope this answers the question. Have a nice day.

5 0
3 years ago
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