7 ig because I mean if you take a look at the problem
Well, there are 3 feet in a yard. So, 3ft=1yrd. Multiply the length value by 3. You could also multiply 3 by the # of yards (or in this situation, 8) Is that good enough?
1) y:10;
2) 4p+6q;
3) x +( x+ 1) = 59 => 2x = 58 => x = 29 => 29 and 30;
