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kari74 [83]
3 years ago
5

If the reaction below takes place at STP how many L of ammonia (NH3) will be formed if one starts with 3.45 moles of hydrogen an

d an excess of nitrogen? Be sure to balance the equation before you begin and round to the proper accuracy. Please leave any units off.
Chemistry
1 answer:
lesya692 [45]3 years ago
6 0

Answer:

51.5 L of ammonia

Explanation:

Ammonia is produced according to this equation:

N₂(g) + 3H₂(g) → 2NH₃ (g)

Let's propose this rule of three:

3 moles of hydrogen can produce 2 moles of ammonia

Then 3.45 moles of hydrogen, will produce (3.45 . 2) / 3 = 2.3 moles of NH₃

We apply the Ideal Gases Law at STP to determine the volume

STP = 1 atm and 273K

1 atm . V = 2.3 mol . 0.082 . 273K

V = (2.3 mol . 0.082 . 273K) / 1 atm = 51.5 L

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16. Formaldhyde has a mole ratio of 1 mole C: 2 moles H: 1 mole O. Its empirical formula is the same as its
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The molecular formula is the actual formula of the compound.

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