Moles = 15.5 g / 40 g/mol = 0.3875 mol
M = 0.3875 mol / 0.250 L = 1.55M
Answer is: <span>the empirical formula of the hydrocarbon is CH</span>₂.<span>
Chemical reaction: C</span>ₓHₐ + O₂ → xC + a/2H₂O.<span>
m(CO</span>₂) = 33.01 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
n(CO₂) = 33.01 g ÷ 44.01 g/mol.
n(CO₂) = n(C) = 0.75 mol.
m(H₂O) = 13.52 g.
n(H₂O) = 13.52 g ÷ 18 g/mol.
n(H₂O) = 0.75 mol.
n(H) = 2 · n(H₂O) = 1.5 mol.
n(C) : n(H) = 0.75 mol : 1.5 mol /0.75 mol.
n(C) : n(H) = 1 : 2.
Answer:
A
Explanation:
I believe it's A gggggg%gggggtggg
Answer:
The answer to your question is letter B.
Explanation:
Process
1.- Calculate the molecular mass of Ferric oxide
Fe = 56g x 2 = 112 g
O = 16 x 3 = 48 g
Mass = 112 + 48 = 160 g
2.- Calculate the mass of 0.7891 moles of Ferric oxide
160 g of Fe₂O₃ ------------- 1 mol
x ------------- 0.7891 mol
x = (160 x 0.7891) / 1
x = 126.2 g
