Answer:
x = 33.52 amu
Explanation:
It is given that,
Isotope A has a mass of 34 amu and an abundance of 52%, isotope B has a mass of 33 amu and an abundance of 48%.
Let x is the average atomic mass of this element. It can be calculated as follows :
So, the average atomic mass of this element is 33.52 amu.
Answer:
C. 11 moles of N2O
Explanation:
A. CO2 exists as a molecular compound. The number of atoms present = 1 atom of Carbon and 2 atoms oxygen = 3 atoms * 9 = 18 atoms
B. Xe exists as an atom. Number of atoms present = 10 * 1 atom = 10 atoms
C. N20 contains 3 atoms; 2 atoms of Nitrogen and 1 atom of oxygen.
Number of atoms present = 3 * 11 = 33 atoms
D. CO contains 2 atoms, 1 each of carbon and oxygen.
Number of atoms present = 12 * 2 = 24 atoms
A group goes vertically and a period goes horizontally.
(a group goes down and a period goes across)
Answer:
See explanation
Explanation:
We know that the process of the oxidation of SO2 to SO3 is catalysed by NO2 gas. It occurs in two stages and i will show the balanced reaction equation of the both stages below;
Step 1
2NO2(g) + 2SO2(g) ------> 2NO(g) + 2SO3(g)
Step 2
2NO(g) + O2(g) -------> 2NO2(g)
So, the overall reaction equation is;
2SO2(g) + O2(g) ------> 2SO3(g)
Hi uhh i've never really typed in Spanish but here I go! :)
Un ano luz es equivalente a 9.467 PM
