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WARRIOR [948]
4 years ago
5

How would you obtain ethanol from rice starch?​

Chemistry
1 answer:
sergejj [24]4 years ago
5 0

Answer:

By putting the rice in water

Explanation:

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how many moles of sodium hydroxide would have to be added to 250 ml of a 0.403 m acetic acid solution, in order to prepare a buf
jonny [76]

The volume of the buffer solution having a ph value is calculated by henderson's hasselbalch equation.

Buffer solution is water based solution which consists of a mixture containing a weak acid and a conjugate base of the weak acid. or a weak base and conjugate acid of a weak base.it is a mixture of weak acid and a base. The pH of the buffer solution is determined by the expression of the henderson hasselbalch equation.

              pH=pKa + log [salt]/[acid]

Where, pKa =dissociation constant , A- = concentration of the conjugate base, [HA]= concentration of the acid. Here, a buffer solution contains 0.403m acetic acid  and 250 ml is added  in order to prepare a buffer with a ph of 4.750. Putting all the values in the henderson hasselbalch equation we find the pH of the buffer solution.

To learn more about hendersons hasselbalch equation please visit:

brainly.com/question/13423434

#SPJ4

6 0
1 year ago
How does mechanical energy depend on other forms of energy??
Ksenya-84 [330]

Answer:

Other forms of energy can convert to mechanical energy

Explanation:

For example the electric or magnetic energy in a motor can convert to mechanical energy, or another example is when you put two magnets together they will clip together due to the magnetic energy that they have.

5 0
3 years ago
Air at 7S°F and14.6 though a cfm(cubic ft per minute) and the The flow rate is 48000 psia flows though a rectangular duct of Ix2
IgorLugansk [536]

Explanation:

The given data is as follows.

Air is at 75^{o}F and 14.6 psia.

\varepsilon = 0.00015 ft,     Flow rate, (Q) = 48000 ft^{3}/m

(a)  Formula to calculate hydraulic radius (r_{H}) is as follows.

              r_{H} = \frac{\text{free flow area}}{\text{wet perimeter}}

                          = \frac{2 \times 1}{2(1) + 2(2)}

                          = \frac{1}{3} ft

Formula for equivalent diameter is as follows.

                     D_{eq} = 4 \times r_{H}

                                    = 4 \times \frac{1}{3} ft  

                                    = \frac{4}{3} ft

(b)    Formula for velocity floe is as follows.

                         Q = VA

                     V = \frac{Q}{A}

                        = \frac{48000}{2 \times 1} ft/min

                        = 24000 ft/min

(c)   Formula to calculate Reynold's number is as follows.

         R_{e} = \frac{D \times V \times \rho}{\mu}

                   = \frac{\frac{4}{3} \times 24000 \times 0.0744}{0.0443}  (as \rho = 0.0744 lb/ft^{3} and \mu = 0.0443 lb/ft. hr)

                   = 53742.66 hr/min  

As 1 hr = 10 min. So, 53742.66 hr/min \times \frac{60 min}{1 hr}

                            = 3224559.6

(d)   Formula to calculate pressure drop (\Delta P) is as follows.

              \frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}

Putting the given values into the above formula as follows.

               \frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}

                      = \frac{4 \times 0.00015 \times 100 \times 0.0744 \times (24000)^{2}}{2 \times \frac{4}{3} \times {4}{3}}

                      = 6.238 lb/ft^{2}

5 0
3 years ago
The rate at which a certain drug is eliminated by the body follows first-order kinetics, with a half life of 68 minutes. Suppose
viva [34]

Answer:

The concentration would be; 0.0038 μgmL

Explanation:

Half life, t1/2 = 68 minutes

Initial Conc. [A]o = 0.12/μgmL

Final Conc [A] = ?

Time. k = 340 minutes

ln[A] = ln[A]o - kt

t1/2 = ln2 / k

k = 0.693 / t1/2  = 0.693 / 68 = 0.01019

ln[A] = ln (0.12) - 0.01019 (340)

ln[A] = -2.1203 -3.4646

ln[A] = -5.5849

[A] = 0.00375 ≈ 0.0038 μgmL

3 0
3 years ago
How many significant figures are in the number 20300?​
arlik [135]

Answer:

There are three significant figures in the number 20300

3 0
3 years ago
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