Hey Geny :)
I’m pretty sure the answer is B
Hope this helps you
-AaronWiseIsBae
Answer:
λ = 0.5×10⁻⁵ m
E = 39.78×10⁻²¹ J
The given radiation is gamma ray.
Explanation:
Given data:
Frequency of radiation = 6.0 ×10¹³ Hz
Wavelength of radiation = ?
Type of radiation = ?
Energy of radiation = ?
Solution:
Formula:
speed of light = wavelength × frequency
3 ×10⁸ m/s = λ × 6.0 ×10¹³ Hz
Hz = s⁻¹
λ = 3 ×10⁸ m/s / 6.0 ×10¹³ s⁻¹
λ = 0.5×10⁻⁵ m
Energy of radiation:
E = hf
h = planck's constant
f = frequency
E = 6.63×10⁻³⁴ j.s × 6.0 ×10¹³ s⁻¹
E = 39.78×10⁻²¹ J
The given radiation is gamma ray.
For the equilibrium that exists in an aqueous solution<span> of nitrous acid (</span>HNO2, a weak acid) ... [H+][NO2. –]. [HNO2<span>]. PAGE: 14.1. 2. Which of the following is a conjugate ... Using the following Ka values, indicate the correct </span>order<span> of base strength. </span>HNO2<span>. Ka = </span>4.0<span> × 10–4 .... Calculate the [H+] in a </span>solution<span>that has a </span>pH<span> of 11.70.
i hope thid works
</span>
In chemistry:
When something is oxidized, it loses electrons.
When something is reduced, it gains electrons.
So the correct statements would be the second to last and third to last statements
