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cupoosta [38]
3 years ago
8

The emission spectrum for an element is? Select all that apply

Chemistry
1 answer:
lesya [120]3 years ago
4 0

Answer:  You didn't give anything to select, however, the emission spectrum of a chemical element is frequencies of electromagnetic radiation emitted due to an atom or molecule making a transition from a high energy state to a lower energy state.

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(c) Which element is in Group V and in period 3​
Lorico [155]

Answer:

Phosphorus

Explanation:

Group V elements- Nitrogen, Phosphorous

period 3- Sodium, Magnesium, Aluminium, Silicon , Phosphorous, Sulphur, Chlorine and Argon

Group v and period 3 is phosphorus

6 0
3 years ago
Most scientists use scientific methods in which of the following orders
igomit [66]

Answer:

Experiment, analysis, research, purpose, hypothesis and conclusion.

6 0
3 years ago
Describe protons. Location: Charge: Mass
PilotLPTM [1.2K]

Answer:

Protons are one of the basic atoms.

Explanation:

Proton's charge: Positive (+)

Proton's location: Usually in the nucleus with neutrons

Proton's mass: 1.67262 × 10⁻²⁷ kg

6 0
3 years ago
Which rate law is consistent with the mechanism?
yulyashka [42]
C I’m pretty sure. The first step is the rate determining step
6 0
3 years ago
How do you know the strength of oxidizing/reducing agents in questions such as these ones? I know the answer for 37 is D but I d
Verdich [7]

Answer:

Pd^{2+} is the strongest oxidizing agent .

Explanation:

It is said in the question that given reactions are spontaneous.

As Np^{3+} oxidizes Ce to  Ce^{3+} we can say that  Np^{3+} is a stronger oxidizing agent than  Ce^{3+}.

Similarly , Cd^{2+} is stronger than  Np^{3+} (from first reaction).

From second reaction we can see that  Pd^{2+} is stronger than  Cd^{2+}.

The order of oxidizing strength is  Pd^{2+} >  Cd^{2+} >  Np^{3+} >  Ce^{3+} .

3 0
3 years ago
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