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Fynjy0 [20]
3 years ago
10

How to solve this equation

Mathematics
1 answer:
mariarad [96]3 years ago
7 0
\bf \sqrt{5x+19}-4=3x-15
\\\\
\sqrt{5x+19}=3x-15+4\\\\ \sqrt{5x+19}=3x-11\leftarrow \textit{square both sides}
\\\\
(\sqrt{5x+19})^2=(3x-11)^2
\\\\
5x+19=(3x-11)^2\qquad 
\begin{cases}
(3x-11)^2\to (3x-11)(3x-11)\\
 --------------\\
\textit{or use FOIL to expand it}
\end{cases}

then solve for "x"
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A group surveyed a mix of people below and above 40 years old about whether or not they visit a dentist once a year. This table
Rama09 [41]

The frequency table that shows the relative frequency of people older than 40 and don't visit the dentist is:

D.                  Visit Dentist Yearly Don’t Visit Dentist Yearly

Below 40                    0.27                         0.73

Above 40                   0.57                          0.43

<h3>What is the relative frequency required?</h3>

The relative frequency of those older than 40 and don't go annually to a dentist can be found as:

= Number of over 40 who don't go to dentist / Total of those over 40 surveyed

Solving gives:

= 13 / (17 + 13)

= 13 / 30

= 0.43

Find out more on relative frequency at brainly.com/question/16832475.

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4 0
2 years ago
3. Try It #3 Write the point-slope form of an equation of a line with a slope of -2 that passes through the point (-2,2). Then r
vova2212 [387]

Answer:

Point-slope form of equation given as $y-2=-2(x+2)$.

Slope-intercept form of equation is given as $y=-2 x-2$.

Step-by-step explanation:

In the question, it is given that the slope of a line is -2 and it passes from (-2,2).

It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.

To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.

Step 1 of 2

Passing point of the line is (-2,2).

Hence, $x_{1}=-2$ and

$$y_{1}=2 \text {. }$$

Also, the slope of the line is -2.

Hence, m=-2

Substitute the above values in point-slope form of equation given by $y-y_{1}=m\left(x-x_{1}\right)$

$$\begin{aligned}&y-y_{1}=m\left(x-x_{1}\right) \\&y-2=-2(x-(-2) \\&y-2=-2(x+2)\end{aligned}$$

Hence, point-slope form of equation given as y-2=-2(x+2).

Step 2 of 2

Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.

$$\begin{aligned}&y-2=-2(x+2) \\&y-2=-2 x-4 \\&y=-2 x-4+2 \\&y=-2 x-2\end{aligned}$$

Hence, slope-intercept form of equation is given as y=-2x-2.

7 0
2 years ago
What is the area of the right triangle with sides 10,26 and 24
solniwko [45]
Answer:

Area = 120

Step-by-step explanation:

Area = 1/2 bh

Area = 1/2 (10)(24)

Area = 1/2 (240)

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3 years ago
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Answer:

See below ↓↓

Step-by-step explanation:

<u>Finding the radius</u>

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<u />

<u>Surface Area</u>

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  • 4 x 3.14 x 4 x 4
  • 3.14 x 64
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<u></u>

<u>Volume</u>

  • 4/3πr³ = 4πr² x r/3
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Which choice is equivalent to the quotient shown here when x &gt; 0
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Answer:

this is equal to √(3x²/12) = √(x²/4) = x/2

Step-by-step explanation:

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