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3 years ago

How to solve this equation

Mathematics

1 answer:

mariarad [96]3 years ago

7 0

$\bf \sqrt{5x+19}-4=3x-15
\\\\
\sqrt{5x+19}=3x-15+4\\\\ \sqrt{5x+19}=3x-11\leftarrow \textit{square both sides}
\\\\
(\sqrt{5x+19})^2=(3x-11)^2
\\\\
5x+19=(3x-11)^2\qquad 
\begin{cases}
(3x-11)^2\to (3x-11)(3x-11)\\
 --------------\\
\textit{or use FOIL to expand it}
\end{cases}$

then solve for "x"

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Exactly 1 1/3 yard of ribbon is needed to make a bow. Which of the following lengths of ribbon could be used to make a bow with

svp [43]

Answer:

1 and 2/5 yards wastes only 1/15 a yard

Step-by-step explanation:

1 and 1/6 yards would make a waste of 1 and 1/6 yards since you can't make a ribbon out of it. (incorrect)

1 and 2/10 yards would make a waste of 1 and 1/5 yards since you can't make a ribbon out of it. (incorrect)

1 and 2/5 yards

$1\frac{2}{5} -1\frac{1}{3} =\\\\1\frac{6}{15} -1\frac{5}{15} =\\\\\frac{1}{15}$

Wastes 1/15 a yard.

1 and 1/2 yards

$1\frac{1}{2} -1\frac{1}{3} =\\\\1\frac{3}{6} -1\frac{2}{6} =\\\\\frac{1}{6}$

It wastes 1/6 a yard.

2 yards

$2-1\frac{1}{3} =\frac{2}{3}$

It wastes 4/6 a yard.

4 0

3 years ago

Ummm yes help me or whatever

Tema [17]

Answer:

i choose whatever

Step-by-step explanation:

yu gave me the option :)

3 0

3 years ago

A total of 243 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student t

alina1380 [7]

Answer:

81 adult tickets

Step-by-step explanation:

Step 1:

Set up a system of equations

Since the adult tickets and student tickets add to 243, we can do

$a+s=243$

and the student tickets sold were 2x the adult tickets, we can do

$s=2a$

We can replace s in the first equation adding to 243 with 2a

$a+s(2a)=243\\3a=243\\$

Step 2:

Solve for a. We can divide both sides by 3.

$a=81$

Therefore, there were 81 adult tickets sold.

Step 3:

We can check our work! Since we learned earlier the student tickets are 2x adult tickets, we can multiply 81 by 2 and add that to 81 to see if it equals 243!

$s=2a\\s=2(81)\\s=162$