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dem82 [27]
3 years ago
5

What is the slope of the line that contains these points?

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
3 0

Answer:

m=-3/7

Step-by-step explanation:

(-4,2), (-3,5)

x1  y1   x2 y2

m=<u>y2-y1</u>

     x2-x1

m=<u>5-2</u>

    -3-4

m=<u>3</u>

   -7

m=-3/7

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Need help with courseReplace 250 with 575 and -3 with -5.
Svetlanka [38]

Given

The demand function

p(x)=\frac{250}{\sqrt{x}}-5

To determine:

a) The revenue function.

b) The marginal revenue.

c) The marginal revenue when x=200.

d) The equation of tangent, and its derivation.

Explanation:

It is given that,

p(x)=\frac{250}{\sqrt{x}}-5

a) The revenue function is given by,

\begin{gathered} R(x)=x\cdot p(x) \\ R(x)=x\times(\frac{250}{\sqrt{x}}-5) \\ R(x)=250\sqrt{x}-5x \end{gathered}

b) The marginal revenue function is,

\begin{gathered} R^{\prime}(x)=\frac{d}{dx}(R(x)) \\ =\frac{d}{dx}(250\sqrt{x}-5x) \\ =250\times(\frac{1}{2}\times x^{-\frac{1}{2}})-5 \\ =\frac{125}{\sqrt{x}}-5 \end{gathered}

c) The marginal revenue when x=200 is,

\begin{gathered} R^{\prime}(200)=\frac{125}{\sqrt{200}}-5 \\ =\frac{125}{10\sqrt{2}}-5 \\ =8.8388-5 \\ =3.8388 \\ =3.84 \end{gathered}

Hence, the marginal revenue is 3.84.

d) Let y=mx+c is the tangent.

Then,

y=3.84x+c

That implies, for y=12.68, and x=200,

\begin{gathered} 12.68=3.84\times200+c \\ 12.68=768+c \\ c=12.68-768 \\ c=-755.32 \end{gathered}

Hence, the equation of tangent is,

y=3.84x-755.32

8 0
1 year ago
Find the measure of angle A
otez555 [7]

Answer:

<A=35

Step-by-step explanation:

70+x+79+x+39=180

2x+188=180

2x=-8

x=-8/2 or -4

<A=x+39

<A=-4+39

<A=35

7 0
3 years ago
3 people can deliver 1000 letters in 30 minutes.
Studentka2010 [4]

Answer:  It would take 1 hour and 30 minutes for one people do it.

If 5 people do it would take less time. If there are 5 people delivering the letters it would take them 12 minutes ti deliver all 1,000 letters.

6 0
3 years ago
A parcel delivery service will deliver a package only if the length plus girth​ (distance around) does not exceed 84 inches. ​(A
Kisachek [45]

Answer:

A. 14x14x28

B. The maximum volume is 5488 cuibic inches

Step-by-step explanation:

The problem states that the box has square ends, so you can express volume with:

v=x^{2} y

Using the restriction stated in the problem to get another equation you can substitute in the one above:

4x+y=84\\\\

Substituting <em>y</em> whit this equation gives:

v=x^{2} (84-4x)\\\\v=84x^{2} -4x^{3}

Now find the limit of <em>x</em>:

\frac{84x^{2}-4x^{3}}{dx}=168x-12x^{2}\\\\x=\frac{168}{12}=14

Find the length:

y=84-4(14)=28

You can now calculate the maximum volume:

v=(14)^{2}(28)= 5488

6 0
3 years ago
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