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Rzqust [24]
3 years ago
8

‘Which reaction would most likely require the use of an inert electrode?

Chemistry
1 answer:
Airida [17]3 years ago
3 0

An inert electrode is made up of non reactive metals like Platinum

An inert is electrode is required in one of the half cells or both the cells if there is no solid conducting metal in either half reaction. Or we can say that if in any half reaction neither product nor reactant is in solid phase.

From the given equations it is clear that

a) in first cell we have Cu and Ag in solid phase in either side

b) In second reaction the iron is in aqueous phase on both the side of reactant and product

so for reduction of iron or in cathodic half cell we need inert electrode [which does not participate in reaction]

Hence answer is

Mg(s)+2Fe^{+3}(aq)-->2Fe^{+2}(aq)+Mg^{+2}(aq)

c) in third reaction Zn and Sn are in solid phase in either side

d) in fourth reaction Al and Ni are in solid phase in either side

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Bezzdna [24]
I believe the answer to this is A. 
7 0
3 years ago
for a theoretical yield of 22 g and actual yield of 13 g, calculate the percent yield for a chemical reaction
sammy [17]

Answer:

59.09%

Explanation:

13/22*100=59.09%

8 0
3 years ago
What is the difference between a substance at low temperature and one at high temperature
givi [52]

Answer:

Explained below.

Explanation:

A substance at low temperature simply means that the average energy of molecular motion in that substance is low while at higher temperature, the average energy of molecular ml tip in that substance is high.

4 0
3 years ago
Given the following equation: Cu + 2 AgNO3 ---> Cu(NO3)2 + 2
Temka [501]

Given the following equation; Cu + 2AgNO3 = Cu(NO3)2 + 2Ag, 48.97 grams of Cu are needed to react with 262g of AgNO3.

<h3>How to calculate mass of substances?</h3>

The mass of a substance can be calculated using the following steps:

Cu + 2AgNO3 = Cu(NO3)2 + 2Ag

1 mole of Cu react with 2 moles of AgNO3

  • Molar mass of AgNO3 = 169.87 g/mol
  • Molar mass of Cu = 63.5g/mol

moles of AgNO3 = 262g/169.87g/mol = 1.54mol

1.54 moles of AgNO3 will react with 0.77 moles of Cu.

mass of Cu = 0.77 × 63.5 = 48.97g

Therefore, given the following equation; Cu + 2AgNO3 = Cu(NO3)2 + 2Ag, 48.97 grams of Cu are needed to react with 262g of AgNO3.

Learn more about mass at: brainly.com/question/6876669

8 0
2 years ago
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In
adell [148]

Answer:

The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is 523.2 kJ.

Explanation:

Step 1:

CaC_2(s) + 2H_2O(g)\rightarrow C_2H_2(g) + Ca(OH)_2(s),\Delta H_1=414.0 kJ...[1]

Step 2 :

6C_2H_2(g) + 3CO_2(g) + 4H_2O(g)\rightarrow 5CH_2CHCO_2H(g) \Delta H_2=132.0kJ..[2]

Adding 6 × [1] and [2]:

6CaC_2(s) + 12H_2O(g)\rightarrow 6C_2H_2(g) + 6Ca(OH)_2(s)

6C_2H_2(g)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)

we get :

6CaC_2(s) + 8H_2O(g)+3CO_2(g)\rightarrow 5CH_2CHCO_2H(g)+ 6Ca(OH)_2(s),\Delta H'=?

\Delta H'=6\times \Delta H_1+\Delta H_2

\Delta H'=6\times 414.0 kJ+132.0kJ

\Delta H'=2,626 kJ

Energy released on formation of 5 moles of acrylic acid = 2,626 kJ

Energy released on formation of 1 mole of acrylic acid:

\frac{ 2,626 kJ}{5 } = 523.2 kJ

7 0
3 years ago
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