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Rzqust [24]
3 years ago
8

‘Which reaction would most likely require the use of an inert electrode?

Chemistry
1 answer:
Airida [17]3 years ago
3 0

An inert electrode is made up of non reactive metals like Platinum

An inert is electrode is required in one of the half cells or both the cells if there is no solid conducting metal in either half reaction. Or we can say that if in any half reaction neither product nor reactant is in solid phase.

From the given equations it is clear that

a) in first cell we have Cu and Ag in solid phase in either side

b) In second reaction the iron is in aqueous phase on both the side of reactant and product

so for reduction of iron or in cathodic half cell we need inert electrode [which does not participate in reaction]

Hence answer is

Mg(s)+2Fe^{+3}(aq)-->2Fe^{+2}(aq)+Mg^{+2}(aq)

c) in third reaction Zn and Sn are in solid phase in either side

d) in fourth reaction Al and Ni are in solid phase in either side

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Is the bond C=O polar or non polar
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Explanation:

Non Polar molecule because of its linear symmetric shape

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The compound known as diethyl ether, commonly referred to as ether, contains carbon, hydrogen, and oxygen. A 1.376 g sample of e
hoa [83]

Answer:

The answer to your question is: C₄H₁₀O

Explanation:

Data

          CxHyOz

mass sample : 1.376 g

mass CO₂ = 3.268 g

mass H₂O = 1.672 g

Process

Reaction

                      CxHyOz  + O₂ ⇒   CO₂  +  H₂O

1.- Calculate the moles and mass of carbon

Molecular mass CO₂ = 44g

                      44 g of CO₂ --------------  12 g of C

                      3.268 g of CO₂  --------    x

                         x = (3.268 x 12) / 44

                        x = 0.891 g of Carbon

                       12 g of carbon -----------  1 mol

                       0.891 g of C     ----------   x

                       x = (0.891 x 1) / 12

                       x = 0.0743 moles of carbon

2.- Calculate the moles and mass of hydrogen

                      18 g of water --------------- 2 g of H

                      1.672 g of H₂O ------------  x

                      x = (1.672 x 2) / 18

                      x = 0.186 g of hydrogen

                      1 g of hydrogen ------------  1 mol of H

                      0.186 g of H       ------------  x

                      x = (0.186 x 1) / 1

                      x = 0.186 moles of H

3.- Calculate the mass of Oxygen and its moles

Mass of Oxygen = 1.376 - 0.891 - 0.186

                           = 0.299 g of O₂

Moles of Oxygen

                             16 g of Oxygen ---------------- 1 mol

                             0.299 g of O    -----------------  x

                             x = (0.299 x 1) / 16

                             x = 0.019 moles of Oxygen

4.- Divide by the lowest number of moles

Carbon         0.0743/ 0.019 = 3.9 ≈ 4.0

Hydrogen     0.186/ 0.019 = 9.7 = 10

Oxygen         0.019/ 0.019 = 1

5.- Write the empirical formula

                              C₄H₁₀O                  

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4 years ago
What is Industrial chemistry?​
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6 0
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Calculate the number of moles CuCl2 necessary to make 50 mL of a 0.15M solution
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 Volume  ⇒ 50 mL in liters : 50 / 1000 = 0.05 L

Molarity of solution ⇒ 0.15 M

Number of moles:

n =  M * V

n = 0.15 * 0.05

n = 0.0075 moles of CuCl2

hope this helps!.

3 0
3 years ago
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