1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
elena55 [62]
2 years ago
11

Draw the Lewis Dot structure for RbIO2.

Chemistry
2 answers:
Lilit [14]2 years ago
8 0

Rubidium Iodite is an Ionic compound made up of Following two ions,


                                1) Rb⁺ (Cation)


                                2) IO₂⁻ (Anion)


Now in order to draw the lewis structure of Iodite ion (poly anion) we will follow following steps,


a) First add up the number of valence electrons of all elements,


So,

                    Number of valence electrons in I     = 7

                    Number of Valence electrons in O1 = 6

                    Number of Valence electrons in O2 = 6

                    Number of negative charges           = 1

                                                                         --------------

                                                                               20


b) Secondly draw I as the central atom surrounded by two oxygen atoms. Connect I with each O atom via a single bond and subtract 2 electrons per bond, so,


                                                             20

                                                             - 4

                                                          -----------

                                                              16


Now, divide these 16 electrons on all elements starting from most electronegative atom. You will find that each oxygen atom will atain 6 electrons in three pairs and I will attain 4 electrons in 2 pairs, after that make a double bond between one O and I so that the formal charge of I gets zero.


Hence, the structure of Iodite will be as shown below,

Rudik [331]2 years ago
6 0

The RbIO₂ compound has a Lewis structure in IO₂⁻

<h3>Further Explanation </h3>

The Lewis formula is used to describe covalent bonds

Lewis structures have a central atom and a terminal atom

The central atom is an atom that is bound to 2 or more other atoms, while a terminal atom is bound to 1 other atom

In describing Lewis's structure the steps that can be taken are:

  • 1. Count the number of valence electrons from atoms in a molecule
  • 2. Give each bond a pair of electrons
  • 3. The remaining electrons are given to the atomic terminal so that an octet is reached
  • 4. If the central atom is not yet octet, free electrons are drawn to the central atom to form double bonds

In the RbIO₂ compound, the bond is an ionic bond that is Rb + and IO₂⁻ so that what Lewis can describe is the I and O bonds in IO₂⁻

Steps to draw the Lewis structure

  • 1. Place atom I in the middle and O atom on the side
  • 2. Draw the electrons that bind each of 2 pairs to form 2 bonds
  • 3. Write down the remaining free electrons after subtracting the bonding electrons
  • 4. The form of a double bond of one O atom with atom I, because there are electrons that have not been paired

From this it was found that atom I did not follow the octet rule because it binds 10 electrons, this is what is called the octet rule which was developed / expanded, whereas in general period 3 elements such as P, Br, I can have electrons exceeding 8 when they bind

<h3>Learn more </h3>

adding electron dots as needed h3c ss ch3

brainly.com/question/6085185

formal charge

brainly.com/question/7190235

ionic bonding

brainly.com/question/1603987

Keywords: Lewis structure, single-bonded, double-bonded, octet

You might be interested in
Find the percent ionization of a 0.337 m hf solution. the ka for hf is 3.5 x 10-4. 1.1 % 1.2 x 10-2 % 3.2 % 3.5 x 10-2 % 4.7 %
Ugo [173]

To determine the percent ionization of the acid given, we make use of the acid equilibrium constant (Ka) given. It is the ration of the equilibrium concentrations of the dissociated ions and the acid. The dissociation reaction of the HF acid would be as follows:<span>

HF = H+ + F-

The acid equilibrum constant would be expressed as follows:

Ka = [H+][F-] / [HF] = 3.5 x 10-4

To determine the equilibrium concentrations we use the ICE table,
         HF             H+              F-
I      0.337           0                 0
C      -x              +x               +x
---------------------------------------------
E    0.337-x        x                   x 

3.5 x 10-4 = [H+][F-] / [HF] 
3.5 x 10-4 = [x][x] / [0.337-x] </span>

Solving for x,

x = 0.01069 = [H+] = [F-]

percent ionization = 0.01069 / 0.337 x 100  = 3.17%

8 0
3 years ago
Read 2 more answers
Are ALL cations positive or negative ions
Mamont248 [21]

Answer:  Ions result from atoms or molecules that have gained or lost one or more valence electrons, giving them a positive or negative charge. Those with a negative charge are called anions and those with a positive charge are called cations. Cations (positively-charged ions) and anions (negatively-charged ions) are formed when a metal loses electrons, and a nonmetal gains those electrons. ... And all of them form an anion with a single negative charge. The VIA elements gain two electrons to form anions with a 2- charge.

hope this helps

7 0
2 years ago
Read 2 more answers
What is the definition of RNA<br>Messenger RNA<br>and <br>Ribosome?<br><br>​
IceJOKER [234]
You can find this on google easily
4 0
2 years ago
Calculate the percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl on the assumption that t
stealth61 [152]

Answer:

1.089%

Explanation:

From;

ν =1/2πc(k/meff)^1/2

Where;

ν = wave number

meff = reduced mass or effective mass

k = force constant

c= speed of light

Let

ν =1/2πc (k/meff)^1/2  vibrational wave number for 23Na35 Cl

ν' =1/2πc(k'/m'eff)^1/2 vibrational wave number for 23Na37 Cl

The between the two is obtained from;

ν' - ν /ν  = (k'/m'eff)^1/2 - (k/meff)^1/2 / (k/meff)^1/2

Therefore;

ν' - ν /ν = [meff/m'eff]^1/2 - 1

Substituting values, we have;

ν' - ν /ν = [(22.9898 * 34.9688/22.9898 + 34.9688) * (22.9898 + 36.9651/22.9898 * 36.9651)]^1/2  -1

ν' - ν /ν = -0.01089

percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl;

ν' - ν /ν * 100

|(-0.01089)|  × 100 = 1.089%

4 0
3 years ago
Thermal Energy Transfer Lab Edge<br> 2021<br> help<br> please
lutik1710 [3]

Answer:

i dont know?

Explanation:

5 0
2 years ago
Read 2 more answers
Other questions:
  • Why don't rockets need air to stay up, like planes do?
    10·1 answer
  • Why are familiar objects such as pens and paper clips not commonly counted in moles?
    14·1 answer
  • Which of these is a harmful interaction?
    7·1 answer
  • 2 Points
    15·2 answers
  • Which molecule will form a solution with a very low pH?<br><br> H3PO4<br> H2O<br> NaOH<br> KOH
    15·2 answers
  • The gradient of a displacement-time graph gives
    7·1 answer
  • There are three ways in which heat be transferred - conduction, convection, and radiation. Which types of thermal transfer invol
    7·1 answer
  • Ughh please help me ​
    8·2 answers
  • PLEASEEE HELP ?!?!?!
    6·2 answers
  • Is anyone good at chemistry if so can someone please help me NO LINKS PLEASE
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!