question 1
by use of Avogadro law
that is,1 mole = 6.02 x10^23 atoms
what about 0.60 moles
by use of cross multipication
=(0.60 mole/ x 6.02 x10^23)/ 1mole = 3.612 x10^23 atoms of Zn
question 2
by use of Avogadro law constant
that is 1 mole =6.02 x10^23 molecules
what about 3.52 x10^24 molecules
by cross multiplication
=( 1 mole x3.52 x10^24 molecules/6.02 x10^23 molecules) = 5.847 moles of water
question 3
by use of Avogadro law constant
1 mole = 6.02 x10^23 atoms
what about 2 moles =? atoms
by use of cross multiplication
=( 2moles x 6.02 x10^23 )/1mole= 1.204 x10^24 atoms of Li
question 4
by use of Avogadro law constant
1 mole = 6.02 x10^23 atoms
what about 6.02 x10^23 atoms =? moles
cross multiplication
(1 mole x6.02 x10^23 atoms)/(6.02 x10^23 atoms)= 1 mole of carbon
question 5
by use Avogadro law constant
1 mole =6.02 x10^23 molecules
what about 4.9 x10^23 moles =? moles
by cross multipication
=( 1mole x 4.9 x10^23 molecules) /6.02 x10^23 molecules = 0.81 moles ZNCl2
Answer:
give us the choices please
Explanation:
Answer:
4.9 x 10⁻⁶.
Explanation:
<em>2H₂O(g) ⇄ 2H₂(g) + O₂(g),</em>
'
P of H₂ = 0.002 atm, P of O₂ = 0.006 atm, and P of H₂O = 0.07 atm.
∴ The equilibrium constant (Kp) = (P of H₂)²(P of O₂)/(P of H₂O)² = (0.002 atm)²(0.006 atm)/(0.07 atm)² = 4.9 x 10⁻⁶.
C= comcentration
V= volume
C1*V1=C2*V2
3.5M*225.mL = xM*750 mL
x=(3.5*225/750) =1.05M≈1.1M
