<h3>Answer:</h3>
It depends:
- 4 if she starts at 4
- 5 if she starts at 0
<h3>Explanation:</h3>
Louise needs to end up a total of 5 times 4 away from zero.
If she starts at 4, which is 1 times 4, then she needs to jump 4 more times, to 2, 3, 4, 5 times 4.
If she starts at 0, then she needs to jump 5 times to 1, 2, 3, 4, 5 times 4. (The values at the end of each jump will be {4, 8, 12, 16, 20}.)
437/19=23
23 miles on 1 gallon of gas.
We have that
t²<span> – 81
</span>
we know that
A difference of two perfect squares, <span> (A</span>²<span> - B</span>²)<span> </span><span>can be factored into </span><span> (A+B) • (A-B)
</span> let
A²-------> t²
B²-------> 9²
then
(t² – 9²)------->(t+9)*(t-9)
the answer is
(t+9)*(t-9)
g(5) means we substitute every x in the equation with a 5.
g(5) = (5)^2 - 4.
g(5) = 21.
Yes use that example and it will help!
