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Mekhanik [1.2K]

3 years ago

6

Which of the following changes would improve the accuracy of the molar mass measurement carried out in this experiment:

1 answer:

aleksandrvk [35]3 years ago

4 0

A. would not help and maybe make it harder to get accurate measurements.

b. would make more delta T which will improve its accuracy

c. will also increase delta T.

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babymother [125]

Answer:

A) 20

B) 40

C) Ca

D) 10

E) 9

F) F

Explanation:

The MASS NUMBER is the number of protons + the number of neutrons.

The ATOMIC NUMBER is the number of protons.

You can take the MASS NUMBER - ATOMIC NUMBER = NUMBER OF NEUTRONS.

Each element is unique and distinguished by the NUMBER OF PROTONS = ATOMIC NUMBER, ie...the number of protons in its nucleus. You can find the element's name and symbol on the Periodic Table.

8 0

2 years ago

A change where compounds are formed or decomposed is a(n) physical change phase change nuclear change chemical change

dimaraw [331]

It's a chemical change because a new compound is formed

4 0

3 years ago

Read 2 more answers

Which of the following is an example of a reaction that you've seen in your everyday life ?

soldier1979 [14.2K]

I believe this pertains to chemical reaction? So my guess would be answer A “Fire burning”

Don’t quote me though lol.

7 0

3 years ago

Read 2 more answers

Convert 43 F to Kevin. (Remember units on your answer and SHOW YOUR WORK)

gavmur [86]

Answer:

279.26K

Explanation:

T(k) = (43 + 459.67)×5/9

502.67 × 5/9

279.26 K

4 0

3 years ago

Imagine that you have a 5.00 L gas tank and a 3.50 L gas tank. You need to fill one tank with oxygen and the other with acetylen

Lorico [155]

Answer:

77.14 atm of pressure should be of an acetylene in the tank.

Explanation:

$2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O$

According to reaction, 2 moles of acetylene reacts with 5 moles of oxygen.

Moles of oxygen= $n_1$

Moles of acetylene = $n_2$

$\frac{n_1}{n_2}=\frac{5 mol}{2 mol}=\frac{5}{2}$

Volume of large tank with oxygen gas, $V_1 = 5.00 L$

Pressure of the oxygen gas inside the tank = $P_1=135 atm$

$RT=\frac{P_1V_1}{n_1}$ ..[1]

Volume of small tank with acetylene gas , $V_2= 3.50 L$

Pressure of the acetylene gas inside the tank = $P_2=?$

$RT=\frac{P_2V_1}{n_2}$ ..[2]

Considering both the gases having same temperature T, [1]=[2]

$\frac{P_1V_1}{n_1}=\frac{P_2V_2}{n_2}$

$P_2=\frac{P_1V_1\times n_2}{V_2\times n_1}$

$=\frac{135 atm\times 5.00 L\times 2}{3.50 L\times 5}=77.14 atm$

77.14 atm of pressure should be of an acetylene in the tank.

8 0

3 years ago