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KiRa [710]
3 years ago
14

How to find valency?​

Chemistry
2 answers:
Pepsi [2]3 years ago
6 0

Answer:

ork out which of the displacement (S), initial velocity (U), acceleration (A) and time (T) you have to solve for final velocity (V).

If you have U, A and T, use V = U + AT.

If you have S, U and T, use V = 2(S/T) - U.

If you have S, U and A, use V = SQRT(U2 + 2AS)

Gnoma [55]3 years ago
5 0
A :-) lets take a atomic number of 5 which is BORON so, the valency will be 8 - atomic number of boron.

Eg : boron ( Z = 5 )
Electronic configuration = k = 2 , L = 3
Valency = 8 - 5
= 3
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Directions: Each set of lettered choices below refers to the numbered statements immediately following it. Select the one letter
maksim [4K]

Answer : The only reaction (C) that shows that the same reactant undergoes both oxidation and reduction.

Explanation :

Disproportionation reaction : It is defined as the reaction in which the same reactant undergoes both oxidation and reduction reaction. It is a redox reaction.

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

(A) The given balanced reaction is,

H_2SeO_4(aq)+2Cl^-(aq)+2H^+(aq)\rightarrow H_2SeO_3(aq)+Cl_2(g)+H_2O(l)

This reaction is a redox reaction but not disproportionation reaction because in this reaction there are two reactants in which chlorine shows oxidation and selenium shows reduction.

(B) The given balanced reaction is,

S_8(s)+8O_2(g)\rightarrow 8SO_2(g)

This reaction is a redox reaction but not disproportionation reaction because in this reaction there are two reactants in which sulfur shows oxidation and oxygen shows reduction.

(C) The given balanced reaction is,

3Br_2(aq)+6OH^-(aq)\rightarrow 5Br^-(aq)+BrO_3^-(aq)+3H_2O(l)

This reaction is a disproportionation reaction because in this reaction only one reactant bromine that shows both oxidation and reduction reaction.

(D) The given balanced reaction is,

Ca^{2+}(aq)+SO_4^{2-}(aq)\rightarrow CaSO_4(s)

This reaction is a combination reaction in which the two reactant react to give a single product. There is no changes in the oxidation state of calcium and sulfate.

(E) The given balanced reaction is,

PtCl_4(s)+2Cl^-(aq)\rightarrow PtCl_6^{2-}(aq)

This reaction is a combination reaction in which the two reactant react to give a single product. There is no changes in the oxidation state of platinum and chlorine.

Hence, the only reaction (C) that shows that the same reactant undergoes both oxidation and reduction.

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3 years ago
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What is the volume, in liters, of 6.8 mol of Kr gas at STP?
Virty [35]

Answer:

\boxed {\boxed {\sf D. \ 152 \ L}}

Explanation:

Any gas at standard temperature and pressure (STP) has a volume of 22.4 liters per mole or 22.4 L/mol. We can create a proportion with this value.

\frac {22.4 \ L \ Kr}{1 \ mol \ Kr}

Multiply both sides of the equation by 6.8 moles of krypton.

6.8 \ mol \ Kr *\frac {22.4 \ L \ Kr}{1 \ mol \ Kr}

The units of moles of krypton will cancel.

6.8 *\frac {22.4 \ L \ Kr}{1 }

The denominator of 1 can be ignored, so this becomes a simple multiplication problem.

68 * 22.4 \ L \ Kr

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If we round to the nearest whole number, the 3 in the tenths place tells us to leave the 2 in the ones place.

152 \ L \ Kr

6.8 moles of krypton gas at standard temperature and pressure is equal to <u>152 liters</u>.

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3 years ago
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