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Vinvika [58]
3 years ago
11

At a particular temperature, the solubility of O₂ in water is 0.0500 M when the partial pressure is 0.120 atm. What will the sol

ubility be when the partial pressure of O₂ is 2.470 atm?
Chemistry
1 answer:
uranmaximum [27]3 years ago
4 0

Answer:

At a partial pressure of 2.470 atm, solubility of O_{2} is 1.03 M

Explanation:

The given problem can be solved by using Henry's law

According to Henry's law at a particular temperature for a particular gas and solvent:                        \frac{S_{1}}{S_{2}}=\frac{P_{1}}{P_{2}}

where, S_{1} and S_{2} are solubility of the gas at a partial pressure of P_{1} and P_{2} respectively.

Here, S_{1}=0.0500M, P_{1}=0.120atm and P_{2}=2.470atm

So, S_{2}=\frac{S_{1}P_{2}}{P_{1}}=\frac{(0.0500M)\times (2.470atm)}{0.120atm}=1.03M

Hence, at a partial pressure of 2.470 atm, solubility of O_{2} is 1.03 M

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