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3 years ago

What do you call a bond between two neutral atoms that share electrons

2 answers:

6 0

A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms

Degger [83]3 years ago

5 0

Idgac im just here so the other guy can be marked as brainliest

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A car moved 20km East and 70km West. What is the distance?

Nutka1998 [239]

Answer:

50km

Explanation:

70km - 20km = 50 kilometers

6 0

3 years ago

An essay that is 530 words over an experiment. <br> EX.<br> Coke vs Mento <br> Invisible Ink

irga5000 [103]

Answer:

<h2><u><em>Coke Zero Case Study Coca Cola is world renowned soft drink. Unfortunately when it comes to taking health into consideration this is one of the last things one should be ingesting into their system.</em></u></h2>

Explanation:

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4 0

4 years ago

7. Given a 32.0 g sample of methane gas (CH), determine the pressure that would be exerted on a container with

pishuonlain [190]

Answer:

P = 58.52 atm

Explanation:

Given data:

Mass of sample = 32.0 g

Pressure of sample = ?

Volume of gas = 850 cm³

Temperature of gas = 30°C

Solution:

Number of moles of gas:

Number of moles = mass/molar mass

Number of moles = 32.0 g/ 16 g/mol

Number of moles = 2 mol

Pressure of gas:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

Now we will convert the temperature.

30+273 = 303 K

850 cm³ × 1L /1000 cm³ = 0.85 L

by putting values,

P× 0.85 L = 2 mol × 0.0821 atm.L/ mol.K × 303 K

P = 49.75 atm.L/ 0.85 L

P = 58.52 atm

5 0

3 years ago

A light source of wavelength, l, illuminates a metal and ejects photoelectrons with a maximum kinetic energy of 1 eV. A second l

madreJ [45]

Explanation:

From first source, kinetic energy ( $K.E_{1}$ ) ejected is 1 eV and wavelength of light is $\lambda$ .

From second source, kinetic energy ( $K.E_{2}$ ) ejected is 4 eV and wavelength of light is $\frac{\lambda}{2}$ .

Relation between work function, wavelength, and kinetic energy is as follows.

K.E = $\frac{hc}{\lambda} - \phi$

where, h = Plank's constant = $6.63 \times 10^{-34}$ J.s

c = speed of light = $3 \times 10^{8}$ m/s

Also, it is known that 1 eV = $1.6 \times 10^{-19}$ J

Therefore, substituting the values in the above formula as follows.

From first source,

$K.E_{1}$ = $\frac{hc}{\lambda} - \phi$

1 eV = $1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\lambda} - \phi$

$1.6 \times 10^{-19} J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (1)

From second source,

$K.E_{2}$ = $\frac{hc}{\lambda} - \phi$

$4 \times 1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\frac{\lambda}{2}} - \phi$

$6.4 \times 10^{-19} J = \frac{2 \times 1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (2)

Now, divide equation (2) by 2. Therefore, it will become

${6.4 \times 10^{-19}J}{2} = \frac{2 \times 1.98 \times 10^{-25} J.m}{2\lambda} - \frac{\phi}{2}$

$3.2 \times 10^{-19}J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \frac{\phi}{2}$ ......... (3)

Now, subtract equation (3) from equation (1), we get the following.

$1.6 \times 10^{-19} = \frac{\phi}{2}$

$\phi$ = $3.2 \times 10^{-19}$

= 2 eV

Thus, we can conclude that work function of the metal is 2 eV.

3 0

4 years ago

What is the ph of with a 4.6 x 10-6 M hydroxide ion concentration?

Lunna [17]

<h3>Answer:</h3>

pH = 8.66

<h3>Explanation:</h3>

The pH refers to the acidity or alkalinity of a solution.
It is calculated by getting the negative logarithm of Hydrogen ions concentration.

pH=-log[H⁺]

In this case;

we are given [OH⁻] as 4.6 x 10^-6 M

We are required to calculate the pH

We need to know that;

pH + pOH = 14

pOH = -log[OH⁻]

To get the pH we can calculate the pOH first,

pOH = -log[4.6 x 10^-6 M]

= 5.34

but, pH + pOH = 14

Therefore, pH = 14 - pOH

= 14 - 5.34

= 8.66

Therefore, the pH of the solution is 8.66

4 0

3 years ago