7 × 10² pounds of Cl₂ would be produced in a typical 8-h operating day.
<h3>What is Stoichiometry ?</h3>
Stoichiometry helps us use the balanced chemical equation to measures quantitative relationships and it is to calculate the amount of products and reactants that are given in a reaction.
<h3>What is Balanced chemical equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactants side is equal to the number of atoms on the product side in an equation.
2Cl⁻ (aq) → Cl (g) + 2e⁻
According to stoichiometry, moles of Cl₂
= 4477 moles
Pounds Cl₂
= 7 × 10² lb
Thus from the above conclusion we can say that 7 × 10² pounds of Cl₂ would be produced in a typical 8-h operating day.
Learn more about Stoichiometry here: brainly.com/question/14935523
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The ________ orbital is degenerate with 5py in a many-electron atom.
<h2>
5px is the correct answer</h2>
The volume of base required to completely neutralize the acid is 3.2 mL of NaOH.
The equation of the reaction is;
2NaOH(aq) + H2SO4(aq) -----> Na2SO4(aq) + 2H2O(l)
From the question;
Concentration of acid CA = 0.426M
Concentration of base CB = 2.658M
Volume of acid VA = 10.00mL
Volume of base VB = ?
Number of moles of acid NA = 1
Number of moles of base NB = 2
Using the relation;
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
VB = CAVANB/CBNA
VB = 0.426M × 10.00mL × 2/ 2.658M × 1
VB = 3.2 mL
Learn more: brainly.com/question/6111443
Hello!
The balanced equation for the
neutralization of KOH is the following:
HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)
To calculate the
volume of HCl required, we can apply the following equation:
So, the required volume of HCl is
541,54 mLHave a nice day!
It changes the rate of growth that cells usually undergo.
