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2 years ago

NEED HELP AND WILL GIVE ALOT OF POINTS

Chemistry

1 answer:

zmey [24]2 years ago

7 0

C. nucleus because that is where most of an atom's weight is located.

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Critique Maria’s laboratory safety procedures.

Svetllana [295]

1.No eating in the lab
2.No running around in the lab
3.Wear gloves while performing experiments
4.Clen your hands before you leave the lab

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3 years ago

Given the name select the correct formula for each ion compound

MariettaO [177]

Please provide more info

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3 years ago

What pressure in mmHg is required to contain 0.02300 mol of nitrogen gas in a 4.200 L container at a temperature of 21.00°C? Rou

kap26 [50]

Answer: 100.3 mmHg

Explanation:

Given that:

Volume of nitrogen gas V = 4.200 L

Temperature T = 21°C

Convert Celsius to Kelvin

(21°C + 273 = 294K)

Pressure P = ?

Number of moles of gas = 0.02300

Molar gas constant R is a constant with a value of 0.0821 atm L K-1 mol-1

Then, apply ideal gas equation

pV = nRT

p x 4.200L = 0.02300 moles x (0.0821 atm L K-1 mol-1 x 294K)

p x 4.200L = 0.555 atm L

p = 0.555 atm L / 4.200L

p = 0.132 atm

Now, convert pressure in atm to mmHg

If 1 atm = 760 mmHg

0.132 atm = (0.132 x 760) = 100.3 mmHg

Thus, 100.3 mmHg of pressure is required

8 0

3 years ago

A galvanic cell is set up with two cells containing a cadmium electrode in 0. 250 m cd(no3)2 solution and an iron electrode in 0

Lesechka [4]

The cell potential is 0.01934 V at 25°C.

<h3>What is a galvanic cell?</h3>

A galvanic cell, also known as a voltaic cell, is an electrochemical cell that converts the chemical energy generated by spontaneous redox reactions into electrical energy.

The main components of a galvanic cell are

Anode – Oxidation occurs at the anode

Cathode – Reduction occurs at the cathode

Salt bridge – consists of electrolytes that are needed to complete the circuit in a galvanic cell.

Half-cells – It is important as reduction and oxidation reactions are separated into compartments.

External circuit – it helps in Conducting the flow of electrons between electrodes

At cathode,

$Cd^{2+}(aq) + 2e^-\rightarrow Cd(s)$

At anode,

$Fe(s)+2e^-\rightarrow Fe^{2+}(aq)$

Overall cell reaction

$Fe(s)+Cd^{2+}(aq)\rightarrow Fe^{2+}(aq) + Cd(s)$

$E^o_{cell} = E^o_{cathode} - E^o_{anode}$

= -0.40 -(0.44) = 0.04 V

Nernst equation is given by

$E_{cell} = E^o_{cell} - \frac{2.303RT}{nF} logQ$

At 25°C

$E_{cell} = E^o_{cell} - \frac{0.0592V}{n} logQ$

Here, n = 2 and log Q = log $\frac{0.250}{0.050}$ = 0.699

$E_{cell}$ = 0.01934 V

The cell potential is 0.01934 V at 25°C

Learn more about galvanic cell:

brainly.com/question/13918634

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3 0

9 months ago

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Lithification is the process of converting sediments into solid rock through compaction and cementation. true or false

mylen [45]

The Statement is True.

7 0

2 years ago