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gavmur [86]
3 years ago
13

Find the area of the composite shape... WILL MARK BRAINIEST

Mathematics
2 answers:
Masteriza [31]3 years ago
8 0

Answer:

324.5m^2

Step-by-step explanation:

To find the area of the composite shape, divide the shape into 3 known shapes and calculate their areas.

SO, here we divide the shape into 2 triangles and 1 rectangle.

Area of rectangle = 15 x 8 = 120m^2

Area of triangle 1 = 1/2 x 7 x 15 = 52.5m^2

Area of triangle 2 = 1/2 x 9 x 8 = 4 x 9 = 32cm^2

Now, the sum of these areas = area of composite shape = 32 + 52.5 + 120 = 204.5m^2

Hope this helps.

Please mark brainiest

Good Luck

Nata [24]3 years ago
6 0

Answer: 52.5 + 36 + 120 = 208.5

208.5 m is your answer.

Step-by-step explanation: To come to this, first you have to break the composite shape into the three different shapes that you see. 2 rectangles and a triangle. From there, you simply solve the area for each individual shape and then add them together as shown in the answer.

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Mathematics I need help please
mel-nik [20]
5 1/7 x 1/9= 36/7 ×1/9= 4/7

8-3/2= 8-1 1/2= 7 1/2
7 0
3 years ago
Solve for x <br><br> 3(x+2)+4(x-5)=10
Natasha_Volkova [10]

Answer:

x=24/7

Step-by-step explanation:

3(x+2)+4(x-5)=10

3x+6+4(x-5)=10

3x+6+4x-20=10

7x+6-20=10

7x-14=20

7x=24

x=24/7

8 0
3 years ago
Four plumbers estimated the length of the radius of a cylindrical pipe. The estimates made by
o-na [289]

Answer:

B. \frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25},  \frac{9}{100}

Step-by-step explanation:

The question is not properly presented. See attachment for proper presentation of question

From the attachment, we have that:

W = \frac{3}{25}

X = \frac{\sqrt{3}}{11}

Y = \frac{9}{100}

Z = \frac{\pi}{24}

Required

Order from greatest to least

First, we need to simplify each of the given expression (in decimals)

W = \frac{3}{25}

W = 0.12

X = \frac{\sqrt{3}}{11}

Take square root of 3

X = \frac{1.73205080757}{11}

X = 0.15745916432

X = 0.16 --- approximated

Y = \frac{9}{100}

Y = 0.09

Z = \frac{\pi}{24}

Take π as 3.14

Z = \frac{3.14}{24}

Z = 0.13083333333

Z = 0.13  --- approximated

List out the results, we have:

W = 0.12    X = 0.16    Y = 0.09    Z = 0.13

Order from greatest to least, we have:

X = 0.16     Z = 0.13      W = 0.12       Y = 0.09

Hence, the order of arrangement is:

X = \frac{\sqrt{3}}{11}     Z = \frac{\pi}{24}      W = \frac{3}{25}      Y = \frac{9}{100}

i.e.

\frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25},  \frac{9}{100}

6 0
3 years ago
O.9c + 1.89r = 17.01 c=18.9 - 2.1r equation answer
ikadub [295]

Answer:

c=18.90-2.1r

Step-by-step explanation:

<u><em>The complete question is</em></u>

A chef bought $17.01 worth of ribs and chicken. Ribs cost 1.89 per pound and chicken costs 0.90 per  pound. The equation 0.90 +1.89r = 17.01 represents the relationship between the quantities in this  situation.

Show that each of the following equations is equivalent to 0.9c + 1.89r = 17.01.

Then, explain when it might be helpful to write the equation in these forms.

a. c=18.9-2.1r. b. r= -10÷2c+9​

we have that

The linear equation in standard form is

0.90c+1.89r=17.01

where

c is the pounds of chicken

r is the pounds of ribs

step 1

Solve the equation for c

That means ----> isolate the variable c

Subtract 1.89r both sides

0.90c=17.01-1.89r

Divide by 0.90 both sides

c=(17.01-1.89r)/0.90

Simplify

c=18.90-2.1r

step 2

Solve the equation for r

That means ----> isolate the variable r

Subtract 0.90c both sides

1.89r=17.01-0.90c

Divide by 1.89 both sides

r=(17.01-0.90c)/1.89

Simplify

r=9-0.48c

therefore

The equation c=18.90-2.1r is equivalent

The equation is helpful, because if I want to know the number of pounds of chicken, I just need to substitute the number of pounds of ribs in the equation to get the result.

4 0
3 years ago
Perfect Pizza has 12 toppings listed on their menuHow many ways could customer choose a pizza that contains 4 different toppings
Feliz [49]

Answer:

3

Step-by-step explanation:

i would say 3 different ways because 4 x 3 = 12

Hope this helps!

6 0
2 years ago
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