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Katen [24]
3 years ago
7

Find all real solutions to the equation below. Choices provided in image.

Mathematics
2 answers:
sertanlavr [38]3 years ago
8 0
(x^2 - 9)(x + 2) = 0
(x - 3)(x + 3)(x + 2) = 0

As any of the 3 above factors can equal zero  the solutions are

x =  3, -3 , -2.

So the answer is E. 
Alex Ar [27]3 years ago
6 0
Given equation (x^2-9)(x+2)=0 ............(1)

By the zero product theorem, when the product of two factors is zero, at least one of the factors equals zero.

Therefore, the solutions of (1) are  solutions of
(x^2-9)=0  and (x+2)=0

For (x^2-9)=0 factor (x+3)(x-3)=0 => x=3 or x=-3
For (x+2)=0 => x=-2

So the solution to equation (1) is S={3,-3,-2)
Which means that none of the first four answer options is correct.
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blsea [12.9K]

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3 years ago
Twice a certain whole number subtracted from 3 times the square of the number leaves 133. Find the number
user100 [1]

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7

Step-by-step explanation:

"a certain whole number" is a number that we don't know, so pick a variable, let's use n

"Twice" means two times, so we'll use 2n for this.

"subtracted from" means the 2n will be AFTER the minus sign.

____ - 2n

What goes in front? "3 times the square of the number" 3n^2

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6 0
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