We are given that
Max's grade on the first math exam was a 94
so, first exam grade =94
His grade on his seond math exam was an 89
so, second exam grade =89
change in grade=(first exam grade)-(second exam grade)
change in grade=94-89
change in grade=5
Percentage = ( change in grade)/( first exam grade) *100
so, percentage is
so,
the percent of change in Max's grade to the nearest whole percentage was 5%..........Answer
X^-2=4. You got it correct:)
Answer:
Solutions given:
Velocity ratio V.R =5
effort =500N
efficiency =80%
magnitude of load=?
mechanical advantage [M.A ]
we have
efficiency =M.A/V.R*100%
80=M.A./5*100
80/100*5=M.A
M.A.=4
again
we have
M.A =load/effort
4=load/500
load=500*4
load=2000N
<h3>
<u>the magnitude of the load is 2000N</u>.</h3>
We can use SOH, CAH and TOA, but first we must find the length of a hypotenuse:
h =
sin (theta)=
2/√13cos ( theta) =
-3/√13tan (theta) =
-2/3cot (theta ) =
-3/2sec (theta) = 1/cos(theta ) =
-√13/3csc(theta ) = 1/ sin (theta) =
√13/2
