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4 years ago

Two thermometers are calibrated, one in degrees Celsius and the other in degrees Fahrenheit.

Physics

1 answer:

sdas [7]4 years ago

8 0

Answer:

The temperature is 233.15 K

Explanation:

Recall the formula to convert degree Celsius (C) into Fahrenheit (F):

$\frac{9}{5} C+32=F$

So if we want the value of degree C to be the same as the value of the degree F, we want the following: C = F

which replacing F with C on the right hand side of the equation above, allows us to solve for C:

$\frac{9}{5} C+32=F\\\frac{9}{5} C+32=C\\\frac{9}{5} C-\frac{5}{5} C =-32\\\frac{4}{5} C==32\\C= \frac{-32\,*\,5}{4} \\C=-40$

This means that -40°C = -40°F

And this temperature in Kelvin is:

-40°C + 273.15 = 233.15 K

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A 5 kg rock is raised 28 m above the ground level. What is the change in its potential energy?

marin [14]

Let's assume that ground level is the height 0 meters. The change in potential energy is going to be gravitational potential energy, which is given by PE=mgh.
ΔPE=mgh-mgy
=mg(h-y)
=50(28-0)
=1400 J

3 0

4 years ago

An uncharged, nonconducting, hollow sphere of radius 10.0cm surrounds a 10.0-μC charge located at the origin of a Cartesian coor

MrMuchimi

The electric flux through the hole is $56.45\ webber$ .

Electric flux is the number of electric field lines cutting through the surface and is measured as surface intregal of electric field over that surface
Mathematically it is given by $\phi_E=E.A \ Nm^2/C$ where E is the electric field and A is the area.
Gauss's law states that electric flux through closed surface is equal to the 1 / ε₀ times the charge enclosed by that surface which is given by Ф = q / ε₀ where q is the central charge and ε₀ is the permittivity of the medium.

It is given , hollow sphere of radius 10.0cm surrounds a 10.0-μC charge.

The whole surface of hollow sphere $= 4\pi r^2$

$= 4\times 3.14\times (10 \times 10^{-2})^2 \\\\= 12.56\times 10^{-2} m^2$

Area of the hole ( both side ) $= 2\times \pi r^2$

$= 2\times 3.14 \times (10^-^3)^2\\= 6.28 \times 10^-^6 m^2$

According to Gauss's theorem, the flow from a particular charge in the center is given by

$\phi= \frac{10\times10^-^6}{8.85\times 10^-^1^2}\\\\\phi=1.13\times10^6$

This flux flows through the surface of the sphere, so the flux per unit area which is given by

$= \frac{ 1.13\times 10^6 }{ 12.56\times 10^-^2} \\\\= 8.99 \times 10^6 \ weber / m^2$

Flux through area of hole is given by :

$= 8.99\times10^6 \times6.28 \times 10^-^6\\ = 56.45 \ weber$

Learn about more electric flux here :

brainly.com/question/26289097

#SPJ4

8 0

2 years ago

Light striking a mirror at a 50° angle will be reflected at an angle _____.

Stells [14]

Equal to 50

law of reflection: angle of incidence equals angle of reflection

5 0

4 years ago

Read 2 more answers

What is the impulse of a 3kg object accelerating from rest to 12m/s?

ale4655 [162]

To find the impulse you multiply the mass by the change in velocity (impulse=mass×Δvelocity). So in this case, 3 kg × 12 m/s ("12" because the object went from zero m/s to 12 m/s).

The answer is 36 kg m/s

6 0

3 years ago

A projectile is fired at v 0 = 381.0 m/s at an angle of θ = 73.5 ∘ , with respect to the horizontal. Assume that air friction wi

Ipatiy [6.2K]

Answer:

Explanation:

velocity of projection, vo = 381 m/s

angle of projection, θ = 73.5°

The formula for the range is

$R=\frac{u^{2}Sin2\theta }{g}$

$R=\frac{381^{2}Sin147 }{9.8}$

R = 8067.4 m

Range in shorten by 34.1 %

So, the new range is

R' = 8067.4 - 34.1 x 8067.4/100

R' = 5316.4 m

5 0

3 years ago