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Sergeeva-Olga [200]
4 years ago
14

Two thermometers are calibrated, one in degrees Celsius and the other in degrees Fahrenheit.

Physics
1 answer:
sdas [7]4 years ago
8 0

Answer:

The temperature is 233.15 K

Explanation:

Recall the formula to convert degree Celsius (C) into Fahrenheit (F):

\frac{9}{5} C+32=F

So if we want the value of degree C to be the same as the value of the degree F, we want the following: C = F

which replacing F with C on the right hand side of the equation above, allows us to solve for C:

\frac{9}{5} C+32=F\\\frac{9}{5} C+32=C\\\frac{9}{5} C-\frac{5}{5} C =-32\\\frac{4}{5} C==32\\C= \frac{-32\,*\,5}{4} \\C=-40

This means that -40°C = -40°F

And this temperature in Kelvin is:

-40°C + 273.15 = 233.15 K

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Answer:

The energy of one photon is 2.21x10⁻²⁴ J. Multiplied by 10²⁵ is 22.10 J.

         

Explanation:  

The energy (E) of a photon is:

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h: is the Planck's constant = 6.62x10⁻³⁴ J.s

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E = h\frac{c}{\lambda} = 6.62 \cdot 10^{-34} J.s\frac{3.00\cdot 10^{8} m/s}{8.97 \cdot 10^{-2} m} = 2.21 \cdot 10^{-24} J

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Now, if we multiply the answer by 10²⁵ we have:

E = 2.21 \cdot 10^{-24} J \cdot 10^{25} = 22.10 J

I hope it helps you!

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<h3>117.6 J</h3>

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