Answer:
the electric field strength of this charge is two times the strength of the other charge
Explanation:
Using the relationship between electric field and the charge, which is inversely proportionality. Let the the magnitude of the first charge be Q and the respective electric field be E. It implies that;
E1/E2 = Q2/Q1
E2 = E1 x Q1/Q2
= E x Q/ (Q/2)
= 2E
Answer:
change of momentum does not depend on the mass of the cars, as the force and time are the same all vehicles have the same change of momentum
Explanation:
Let's look for the speed of the car
F = m a
a = F / m
We use kinematics to find lips
v = v₀ + a t
v = v₀ + (F / m) t
The moment is defined by
p = m v
The moment change
Δp = m v - m v₀
Let's replace the speeds in this equation
Δp = m (v₀
+ F / m t) - m v₀
Δp = m v₀ + F t - m v₀
Δp = F t
We see that the change of momentum does not depend on the mass of the cars, as the force and time are the same all vehicles have the same change of momentum
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