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vredina [299]
3 years ago
13

How are the values of the 3s in 33,000 related​

Mathematics
1 answer:
professor190 [17]3 years ago
3 0

Answer: The three in the ten thousand place is 10 times the value of the three in the thousands place. And the three in the thousands place is 10 times smaller than the value of the three in the ten thousand place.

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what is 7 divided by 1/3 in multiplication is it A.1/3 multiplied by 7 =k B. 1/3 multiplied by k=7 or C. 1/3=k multiplied by 7.
NeX [460]

Answer:

B. 1/3 multiplied by k=7

Step-by-step explanation:

7 ÷ ⅓ = k

Multiply both sides by ⅓

7 ÷ ⅓ × ⅓ = k × ⅓

7 = k × ⅓

4 0
3 years ago
What is the value of y in the triangle ?
Rina8888 [55]

Answer:

c

Step-by-step explanation:

hope it helps

6 0
3 years ago
Easton is going to invest $340 and leave it in an account for 8 years. Assuming the interest is compounded quarterly, what inter
Jlenok [28]

Answer:

100.7%

Step-by-step explanation:

Since the interest is compounded quarterly, and there are 4 quarters per year, that would leave us with 32 quarters total where interest is acquired. Now, we need to find the interest rate, that would be required in order to end up with 420 dollars after 32 quarters.

We can setup a formula using our period of time and the money he invested into the bank:

340(x)^{32}=420

We can divide 340 from both sides, and simplify the right side to 21 divided by 17:

x^{32}=\frac{21}{17}

Taking the 32th root of 21/17 is equal to 1.00662, which is equal to 100.0662%. To the nearest tenth of a percent, this is equal to 100.7%.

5 0
2 years ago
Write the equation of a line that passes through the points ( 2 , - 5 ) and ( 8 , - 2 ).
Zielflug [23.3K]

Answer:

y = 1/2x - 6

Step-by-step explanation:

y2 - y1 / x2 - x1

-2 - (-5) / 8 - 2

3 / 6

= 1/2

y = 1/2x + b

-5 = 1/2(2) + b

-5 = 1 + b

-6 = b

3 0
3 years ago
New codes to destroy the First Order are known to exist. With probability 0.6, the codes are hidden by Leia; with probability 0.
elixir [45]

Answer: (a). 0.62 (b). 0.53

Step-by-step explanation:

Let us start by defining some events seen:

Given;

L rep the event that codes hidden Leia

BB represents the codes hidden in BB-8

H is the event that codes hidden by Hah

C-3PO rep the codes hidden in C3PO

Giving the probabilities, we have that

P(L)  =  probability that codes are hidden by Leia = 0.6

P(H) = probability that codes are hidden by Hah = 0.4

where P(BB/L) = 70/10 i.e 70%

P(C-3PO/L) = 1 - P(BB/L) = 1 - 7/10 = 3/10

Also, P(BB/H)  = 1/2 = P(C-3PO/H)

We can say that Han Solo is likely to hide them in aceta BB-8 and C-3PO

To begin,

(a). The question tell us to find the probability that the codes are with BB-8.

First of all, we find P(BB).

P(BB) = P(L)*P(BB/L) + P(H)*P(BB/H)

solving this we get

P(BB) = 0.6*7/10 + 0.4*1/2 = 0.62

Therefore,  the probability that the codes are with BB-8 = 0.62

(b). The second question says;

Given that the codes are with C-3PO, what is the probability the codes were hidden by Han Solo?

This tell us to find P(H/C-3PO)

P(H/C-3PO) = P(C-3PO/H)*P(H) / P(C-3PO/H) + P(C-3PO/L)*P(L)

inputting the values gives us;

P(H/C-3PO) = 1/2 * 0.4 / ( 1/2 *0.4 + 3/10 *0.6) = 0.53

SO we have that the probability the codes were hidden by Han Solo = 0.53

cheers I hope this was helpful!!

3 0
3 years ago
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