When prices are rising, the Cost of Goods Sold according to LIFO will be <u>higher </u>than cost of goods sold under FIFO.
Last-In, First-Out (LIFO) refers to a company selling off the latest inventory that it receives first before the inventory it received earlier.
When prices are rising, LIFO will result in a higher COGS because:
- Purchases will be high
- Closing stock will be low on account of only the earlier cheaper inventory being left
In conclusion, LIFO results in cost of goods sold being higher because the closing stock which is deducted from COGS will be lower.
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Answer:
See below
Explanation:
Required 1
Overhead rate
= Overhead costs ÷ Direct material cost
= [$612,000 ÷ $1,800,000] × 100
= 34%
Required 2
Total cost of job in process
$90,000
Less: Materials cost of job in process
($27,000)
Less: Overhead applied (34% × $27,000)
($9,180)
Direct labor cost
$53,820
Yes you can. The hand book says a minor and minors are under 18. I hope I helped you.
Answer:
Scenario analysis
Explanation:
Scenario analysis is defined as the process of analysing future occurences by choosing present alternatives. It shows different future possibilities of an event, and not just one.
It is a for of projection analysis.
For example the manager's analysis is: if a severe earthquake occurred while the company was filming a movie, there could be deaths and injuries, destruction of movie sets, delays in production, costs associated with filming at an alternative location, and loss of reputation and good will.
Answer:
A) R(x) = 120x - 0.5x^2
B) P(x) = - 0.75x^2 + 120x - 2500
C) 80
D) 2300
E) 80
Explanation:
Given the following :
Price of suit 'x' :
p = 120 - 0.5x
Cost of producing 'x' suits :
C(x)=2500 + 0.25 x^2
A) calculate total revenue 'R(x)'
Total Revenue = price × total quantity sold, If total quantity sold = 'x'
R(x) = (120 - 0.5x) * x
R(x) = 120x - 0.5x^2
B) Total profit, 'p(x)'
Profit = Total revenue - Cost of production
P(x) = R(x) - C(x)
P(x) = (120x - 0.5x^2) - (2500 + 0.25x^2)
P(x) = 120x - 0.5x^2 - 2500 - 0.25x^2
P(x) = - 0.5x^2 - 0.25x^2 + 120x - 2500
P(x) = - 0.75x^2 + 120x - 2500
C) To maximize profit
Find the marginal profit 'p' (x)'
First derivative of p(x)
d/dx (p(x)) = - 2(0.75)x + 120
P'(x) = - 1.5x + 120
-1.5x + 120 = 0
-1.5x = - 120
x = 120 / 1.5
x = 80
D) maximum profit
P(x) = - 0.75x^2 + 120x - 2500
P(80) = - 0.75(80)^2 + 120(80) - 2500
= -0.75(6400) + 9600 - 2500
= -4800 + 9600 - 2500
= 2300
E) price per suit in other to maximize profit
P = 120 - 0.5x
P = 120 - 0.5(80)
P = 120 - 40
P = $80
