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melomori [17]
3 years ago
10

The normal boiling point of a certain liquid is , but when of urea () are dissolved in of the solution boils at instead. Use thi

s information to calculate the molal boiling point elevation constant of . Be sure your answer is rounded to the correct number of significiant digits.
Physics
1 answer:
Kruka [31]3 years ago
5 0

Answer:

100 Degrees is boiling point.

Explanation:

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Three very small spheres of mass 2.50 kg, 5.00 kg, and 8.00 kg are located on a straight line in space away from everything else
Aliun [14]

Answer:

The <em>net gravitational force it exerts</em> is F_{net}=9.66*10^{-8}N

Explanation:

Newton's Law of Gravitation can be written as

F=\frac{Gm_{1}m_{2}}{r^{2} }

where <em>G is the Gravitational Constant, m1 and m2 are the masses of two objects, and r is the distance between them</em>. In this case, the spheres are loacted in straight line, so instead of a vector r, we have a distance x in meters. The distances and masses are given in the problem, and the smaller sphere is between the other two spheres. This means <u>the sphere 1 is in the middle, the sphere 2 is on the left of 1, and the sphere 3 is on the right of 1</u>, so

F_{21} =\frac{Gm_{1}m_{2}}{x_{21}^{2} } is the force that 2 feels because of 1, and

F_{31} =\frac{Gm_{1}m_{3}}{x_{31}^{2} } is the force that 3 feels because of 1.

<em>If we replace the data in those previous equations</em>, we have that

F_{21} =\frac{G(2.5)(5) }{(0.08)^{2} }=1.3*10^{-7}N

F_{31} =\frac{G(2.5)(8) }{(0.2)^{2} }=-3.34*10^{-8}N

Finally, adding both results, the net force the sphere 1 exerts is

F_{net}=9.66*10^{-8}N

6 0
3 years ago
Nuclear energy is currently used in which three kinds of vehicles?
USPshnik [31]
Its d. Airplanes, submarines, ships
6 0
3 years ago
(Fill In The Blanks Plz)
Mice21 [21]

Answer:

No. of Molecules = 18.06 x 10²³ molecules

No. of Atoms of P = 3 atoms

No. of Atoms of Na = 9 atoms

Total No. of Atoms = 24 atoms

Explanation:

<u>FOR NUMBER OF MOLECULES</u>:

No.\ of\ Molecules = (No.\ of\ Moles)(Avigadro's\ Number)\\No.\ of\ Molecules = (3)(6.02\ x\ 10^{23}\ molecules})\\

<u>No. of Molecules = 18.06 x 10²³ molecules</u>

<u></u>

<u>FOR NUMBER OF P ATOMS</u>:

No.\ of\ Atoms\ of\ P = (No.\ of\ Moles)(N.\ of atoms of P)\\No.\ of\ Atoms\ of\ P = (3)(1\ atom})

<u>No. of Atoms of P = 3 atoms</u>

<u></u>

<u>FOR NUMBER OF Na ATOMS</u>:

No.\ of\ Atoms\ of\ Na = (No.\ of\ Moles)(N.\ of atoms of Na)\\No.\ of\ Atoms\ of\ Na = (3)(3\ atom})

<u>No. of Atoms of Na = 9 atoms</u>

<u></u>

<u>FOR TOTAL NUMBER OF ATOMS</u>:

Total\ No.\ of\ Atoms = (No.\ of\ Moles)(N.\ of\ atoms\ of\ Na + No.\ of\ atoms\ of\ P + No.\ of\ atoms\ of\ O)\\ Total\ No.\ of\ Atoms\ = (3)(3\ atoms + 1\ atom + 4\ atoms}) = (3)(8\ atoms)

<u>Total No. of Atoms = 24 atoms</u>

<u></u>

<u></u>

8 0
3 years ago
A long iron bar lies along the x-axis and has current of I = 16.4 A running through it in the +x-direction. The bar is in the pr
Gre4nikov [31]

Answer:

B = 8.0487mT

Explanation:

To solve the exercise it is necessary to take into account the considerations of the Magnetic Force described by Faraday,

The magnetic force is given by the formula

F =BILsin\theta

Where,

B = Magnetic Field

I = Current

L = Length

\theta = Angle between the magnetic field and the velocity, for this case are perpendicular, then is 90 degrees

According to our data we have that

I = 16.4A

F = 0.132N/m

As we know our equation must be modificated to Force per length unit, that is

\frac{F}{L} = BI sin(90)

Replacing the values we have that

0.132 = 16.4 (1) B

Solving for B,

B = \frac{0.132}{16.4}

B = 8.0487mT

8 0
4 years ago
A bowling ball has a mass of 6 kg. What happens to its momentum when its speed increases from 2 m/s to 4 m/s?
mash [69]

Answer:

B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s

Explanation:

The momentum of an object is given by the product between its mass (m) and its velocity (v):

p=mv

Let's apply this formula to calculate the initial momentum and final momentum of the ball:

- initial momentum:

p_i = m v_i = (6 kg)(2 m/s)=12 kg m/s

- Final momentum:

p_f = m v_f = (6 kg)(4 m/s)=24 kg m/s

So, the correct answer is

B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s

3 0
3 years ago
Read 2 more answers
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