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Arte-miy333 [17]
3 years ago
15

A posição de um veículo no trecho reto de uma estrada, durante um certo tempo e a partir de um estabelecido referencial, tem a s

eguinte forma: S = – 4,0 + 40t (no MKS). Pode-se afirmar que:
a) Seu movimento é retrógrado.



b) Sua aceleração centrípeta é nula.



c) Ele inverte o sentido de movimento em t = 16 s.



d) Ele passa na origem dos espaços no instante t = 80 s.
Physics
1 answer:
Mariulka [41]3 years ago
4 0

Answer:

b) Sua aceleração centrípeta é nula.

Explanation:

a)

Movimento Retrógrado é o movimento descrito por um móvel cujo movimento vai  percorrendo em sentido contrário ao da reta.

É descrito matematicamente por uma função linear <u>decrescente</u>.

Analisando a função abaixo, percebe-se que esse movimento não é retrógrado. Haja vista, ser esta função crescente uma vez que o sinal da constante "v" é positivo.

S=-4+40t

Vamos testar para verificar

S=-4+4(1) \therefore S=0\\S=-4+40(2) \therefore S=-4+80 \therefore S=76 m\\S= -4 +40(3) \therefore S=-4+120 \therefore S=116 metros

b)

A Aceleração centrípeta está diretamente ligada ao Movimento Circular, podemos calculá-la por

a_{cp}=\frac{v^{2}}{R}

Como a função S=-4+4t descreve um movimento linear, sua aceleração centrípeta é nula, pois não há Movimento Circular sendo executado pelo móvel. Assim, não há Raio

Logo:

c)  Para que houvesse inversão de sentido, o valor de S teria que ser negativo. Fazendo a substituição vemos que isso não ocorre:

S=-4+40*16\\S=-4+640\\S=636 m

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