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mel-nik [20]
2 years ago
7

Between 1992 and today, astronomers using large telescopes have discovered many icy pieces that orbit in the same region as the

orbit of Pluto. These are believed to be members of the
Physics
1 answer:
pantera1 [17]2 years ago
6 0

Icy pieces that orbit in the same region as the orbit of Pluto are believed to be members of the Kuiper belt.

<h3>What is the Kuiper belt?</h3>

The Kuiper belt is a shape-disc formation in the solar system observed from Neptune and more away from our sun.

The Kuiper belt consists of different celestial bodies including among others icy pieces, planets, and comets.

In conclusion, icy pieces that orbit in the same region as the orbit of Pluto are believed to be members of the Kuiper belt.

Learn more about the Kuiper belt here:

brainly.com/question/3955749

#SPJ1

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Answer:

College student's commitment

Explanation:

The dependent variable is  the college students since it  is the variable we are going to measure as a result of the independent variable which is  the hazardous hazing ritual or non-hazardous hazing ritual.

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Which formula correctly shows how to calculat the time taken, given the average velocity and the displacement
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The first answer should be correct if not then the second one
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A powerful searchlight shines on a man. The man's cross-sectional area is 0.500m2 perpendicular to the light beam, and the inten
babymother [125]

Answer:

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵N

(b) the force the light beam exerts is much too small to be felt by the man.

Explanation:

Given;

cross-sectional area of the man, A = 0.500m²

intensity of light, I = 35.5kW/m²

If all the incident light were absorbed, the pressure of the incident light on the man can be calculated as follows;

P = I/c

where;

P is the pressure of the incident light

I is the intensity of the incident light

c is the speed of light

P = \frac{I}{c} =\frac{35500}{3*10^8} = 1.18*10^{-4} \ N/m^2

F = PA

where;

F is the force of the incident light on the man

P is the pressure of the incident light on the man

A is the cross-sectional area of the man

F = 1.18 x 10⁻⁴ x 0.5 = 5.9 x 10⁻⁵ N

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵ N

Therefore, the force the light beam exerts is much too small to be felt by the man.

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