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mel-nik [20]
2 years ago
7

Between 1992 and today, astronomers using large telescopes have discovered many icy pieces that orbit in the same region as the

orbit of Pluto. These are believed to be members of the
Physics
1 answer:
pantera1 [17]2 years ago
6 0

Icy pieces that orbit in the same region as the orbit of Pluto are believed to be members of the Kuiper belt.

<h3>What is the Kuiper belt?</h3>

The Kuiper belt is a shape-disc formation in the solar system observed from Neptune and more away from our sun.

The Kuiper belt consists of different celestial bodies including among others icy pieces, planets, and comets.

In conclusion, icy pieces that orbit in the same region as the orbit of Pluto are believed to be members of the Kuiper belt.

Learn more about the Kuiper belt here:

brainly.com/question/3955749

#SPJ1

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A car moving around a circular track with constant speed (Select all that apply.) has an acceleration with a direction that cann
BARSIC [14]

Answer:

Explanation:

Has an acceleration directed towards center of its path

5 0
3 years ago
6. A 4 kg object hangs below a 6 kg object by a string of negligible mass. If the 6 kg object is pulled upward by a force of 440
MrRissso [65]

Answer:

T =176 N

Explanation:

from diagram

F -(m_1+m_2_g) = (m_1+m_2_g)a

440 - (6+4)g = (6+4)a

a =\frac{440-10*9.8}{10}

a =34.2 m/s^2

frrom free body diagram of mass m2 = 4kg

T -m_2g =m_2a

T = m_2(g +a)

T = 4(9.81+34.2)

T =176 N

7 0
3 years ago
A 1000 kg elevator is accelerated upward at a rate of 0.70 m/s2. What is the tension in the cable pulling the elevator upward wh
Masteriza [31]

Answer:

Tension is also known as Force...

and Force is mass× acceleration.

so....1000×0.70=700N

5 0
4 years ago
Read 2 more answers
A 0.49-kg cord is stretched between two supports, 7.8m apart. When one support is struck by a hammer, a transverse wave travels
katovenus [111]

To solve this problem we will apply the laws of Mersenne. Mersenne's laws are laws describing the frequency of oscillation of a stretched string or monochord, useful in musical tuning and musical instrument construction. This law tells us that the velocity in a string is directly proportional to the root of the applied tension, and inversely proportional to the root of the linear density, that is,

v = \sqrt{\frac{T}{\mu}}

Here,

v = Velocity

\mu= Linear density (Mass per  unit length)

T = Tension

Rearranging to find the Period we have that

T = v^2 \mu

T = v^2 (\frac{m}{L})

As we know that speed is equivalent to displacement in a unit of time, we will have to

T = (\frac{L}{t}) ^2(\frac{m}{L})

T = (\frac{7.8}{0.83})^2 (\frac{0.49}{7.8})

T = 5.54N

Therefore the tension is 5.54N

8 0
3 years ago
At one atmosphere of pressure and 25°C, a hot air balloon has a volume of 4,000 liters. While still tied to the ground, the air
yawa3891 [41]

Based on the options given, the most likely answer to this query is C) 4577 liters.

Upon computation of the given variables the result seems to be 4577 L

Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
3 0
3 years ago
Read 2 more answers
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