Between 1992 and today, astronomers using large telescopes have discovered many icy pieces that orbit in the same region as the
1 answer:
You might be interested in
Answer:
A protractor to measure the angle of the inclined plane with the horizontal
Explanation:
The student needs to lift the free end of the adjustable inclined plane until the object barely starts sliding, and measure the angle at which such happens. At that point, the force of friction equals the component of the weight in the direction of the incline. That is:
and
Then
and therefore, the coefficient of static friction is fully determined just by calculating the tangent of the angle that the incline forms with the horizontal.
Then the only extra instrument needed is a protractor to measure the angle.
<h2>Answer:</h2>
400N/m
<h2>Explanation:</h2>When n identical springs of stiffness k, are attached in series, the reciprocal of their equivalent stiffness (1 / m) is given by the sum of the reciprocal of their individual stiffnesses. i.e
= ∑ⁿ₁ [
] -----------------------(i)
That is;
=
+
+
+ . . . +
-------------------(ii)
If they have the same value of stiffness say s, then equation (ii) becomes;
= n x
-----------------(iii)
Where;
n = number of springs
From the question,
There are 3 identical springs, each with stiffness of 1200N/m and they are attached in series. This implies that;
n = 3
s = 1200N/m
Now, to calculate the effective stiffness,m, (i.e the stiffness of a longer spring formed from the series combination of these springs), we substitute these values into equation (iii) above as follows;
= 3 x
=
=
Cross multiply;
m = 400N/m
Therefore, the stiffness of the longer spring is 400N/m
24km/hour=(20/3)m/s
Hence, W=1/2*1168kg*[(20/3)/m/s]^2=25955.56J
Hence, W=1/2*1168kg*[(20/3)/m/s]^2=25955.56J