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balandron [24]
3 years ago
5

For a bronze alloy, the stress at which plastic deformation begins is 294 MPa and the modulus of elasticity is 121 GPa. (a) What

is the maximum load that can be applied to a specimen having a cross-sectional area of 327 mm2 without plastic deformation? (b) If the original specimen length is 129 mm, what is the maximum length to which it may be stretched without causing plastic deformation?
Physics
1 answer:
FromTheMoon [43]3 years ago
7 0

Answer:

a) load in Newton is 96,138 b) 129.314mm

Explanation:

Stress = force/ area (cross sectional area of the bronze)

Force(load) = 294*10^6*327*10^-6 = 96138N

b) modulus e = stress/ strain

Strain = stress/ e = (294*10^6)/ (121*10^ 9) = 2.34* 10^ -3

Strain = change in length/ original length = DL/ 129

Change in length DL = 129 * 2.34*10^ -3 = 0.31347

Maximum length = change in length + original length = 129.314mm

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The average velocity for the time period beginning when t=1 and lasting

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The question is incomplete. Find out the complete question below:

If a ball is thrown straight up into the air with an initial velocity of 80 ft/s, it height in feet after t second is given by  y=80t-16t^2 .Find the average velocity for the time period beginning when t=1 and lasting

(i) 0.01 seconds

(ii) 0.001 seconds

Learn more about average velocity at brainly.com/question/6504879

#SPJ4

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2 years ago
. Let us say that you put a cup of cold water in one room and a cup of hot water in
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Answer:

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PLEASE HELP ME !!!
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