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2 years ago

SCIENCE<3:: will give brainliest! :)

Physics

2 answers:

serious [3.7K]2 years ago

8 0

Answer:

I think it's B. there is a cold air mass pushing warm air mass up and replacing it over San Francisco

Alex777 [14]2 years ago

7 0

Answer:

Option two

Explanation:

im smort

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In triangle ABC, the angles A and B have the same measure, while the measure of angle C is 21degrees larger than the measure o

Lynna [10]

180 = 2x+x+21
159 = 3x
x = 53
Angle A = 53°
Angle B = 53°
Angle C = 53+21 = 74°

7 0

3 years ago

Which of the following statements is correct? Which of the following statements is correct? The more a muscle shortens, the more

NeX [460]

The correct answer are

a) "The number of muscle fibers best determines how powerful a muscle will be"

b) "The more a muscle shortens, the more power it generates."

Reason :

Muscle fiber in longitudinal directions generate more power

Multipennate muscles do not produce much power because the tendon branches within muscle .

4 0

3 years ago

What is the genotype for a woman with no freckles?

SIZIF [17.4K]

Well are having freckles recessive or dominant?

6 0

3 years ago

Read 2 more answers

A pendulum is set in motion and time. The time measured for 20 complete swings is 308.

laiz [17]

Answer:

solution

308=20 swings

?::: =1

( 308×1)÷20

308÷20

154÷10

=15.4

=15.4

6 0

3 years ago

A bowling ball of mass 5.8 kg moves in a straight line at 4.34 m/s How fast must a Ping-Pong ball of mass 2.214 g move in a stra

lilavasa [31]

Answer: 11369.46 m/s

Explanation:

We have the following data:

$m_{1}=5.8 kg$ is the mass of the bowling ball

$V_{1}=4.34 m/s$ is the velocity of the bowling ball

$m_{2}=2.214 g \frac{1 kg}{1000 g}=0.002214 kg$ is the mass of the ping-pong ball

$V_{2}$ is the velocity of the ping-pong ball

Now, the momentum $p_{1}$ of the bowling ball is:

$p_{1}=m_{1}V_{1}$ (1)

$p_{1}=(5.8 kg)(4.34 m/s)$

$p_{1}=25.172 kg m/s$ (2)

And the momentum $p_{2}$ of the ping-pong ball is:

$p_{2}=m_{2}V_{2}$ (3)

If the momentum of the bowling ball is equal to the momentum of the ping-pong ball:

$p_{1}=p_{2}$ (4)

$m_{1}V_{1}=m_{2}V_{2}$ (5)

Isolating $V_{2}$ :

$V_{2}=\frac{m_{1}V_{1}}{m_{2}}$ (6)

$V_{2}=\frac{25.172 kg m/s}{0.002214 kg}$ (7)

Finally:

$V_{2}=11369.46 m/s$

6 0

3 years ago