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Alchen [17]
3 years ago
10

Can someone please help me out with this question thanks

Physics
1 answer:
IrinaK [193]3 years ago
8 0

Answer:

1.98V

Explanation:

V =IR

V =Voltage

I =Current

R = ResistanceV =IR\\V = 100 (0.0198)\\V = 1.98 volts\\Voltage 1.98V

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Question 2 (5 points)
d1i1m1o1n [39]

Answer:

Frequency of sound wave = 198.83 hertz (Approx.)

Explanation:

Given:

Velocity of sound wave in air = 340 m/s

Wavelength = 1.71 meter

Find:

Frequency of sound wave

Computation:

Frequency = Velocity / Wavelength

Frequency of sound wave = Velocity of sound wave in air / Wavelength

Frequency of sound wave = 340 / 1.71

Frequency of sound wave = 198.8304

Frequency of sound wave = 198.83 hertz (Approx.)

6 0
3 years ago
Where an electric field line crosses an equipotential surface, the angle between the field line and the equipotential is
n200080 [17]

Answer:

90 degree

Explanation:

Electric field line is vertical to the electric field line.

4 0
2 years ago
When a space shuttle was launched, the astronauts aboard experienced and acceleration of 29.0 m/s. If one of the astronauts had
ankoles [38]

             Net force = (mass) · (acceleration)

                           = (69 kg) · (29 m/s²)

                           = (69 · 29) · (kg·m/s²)

                           =    2,001  Newtons upward
                         (about  450 pounds)
7 0
3 years ago
1:a boy 2 a girl pulling a heavy crate at the same time w/10 unite of force each.What is the net force acting on the object
vovangra [49]
The maximum magnitude of the net force on the box is 20 N, which is only possible if the boy and the girl pull the box together in the same direction, horizontally and parallel to the ground.
The minimum magnitude of the net force on the box is 0 N, which will occur when the boy and the girl pull the box together in the parallel but opposite direction.
If either of them pulls at an angle from the horizontal, then the magnitude of the net force will be between 0 N and 20 N.
8 0
3 years ago
An electron with kinetic energy 2.9 keV moving along the positive direction of an x axis enters a region in which a uniform elec
Vladimir79 [104]

The electric force on the electron is opposite in direction to the electric field E. E points in the -y direction, so the electric force will point in the +y direction. The magnitude of the electric force is given by:

F = Eq

F = electric force, E = electric field strength, q = electron charge

We need to set up a magnetic field such that the magnetic force on the electron balances out the electric force. Since the electric force points in the +y direction, we need the magnetic force to point in the -y direction. Using the  reversed right hand rule, the magnetic field must point in the -z direction for this to happen. Since the direction is perpendicular to the +x direction of the electron's velocity, the magnetic force is given by:

F = qvB

F = magnetic force, q = charge, v = velocity, B = magnetic field strength

The electric force must equal the magnetic force.

Eq = qvB

Do some algebra to isolate B:

E = vB

B = E/v

Let's solve for the electron's velocity. Its kinetic energy is given by:

KE = 0.5mv²

KE = kinetic energy, m = mass, v = velocity

Given values:

KE = 2.9keV = 4.6×10⁻¹⁶J

m = 9.1×10⁻³¹kg

Plug in and solve for v:

4.6×10⁻¹⁶ = 0.5(9.1×10⁻³¹)v²

v = 3.2×10⁷m/s

B = E/v

Given values:

E = 7500V/m

v = 3.2×10⁷m/s

Plug in and solve for B:

B = 7500/3.2×10⁷

B = 0.00023T

B = 0.23mT

3 0
3 years ago
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