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4 years ago

Can someone please help me out with this question thanks

Physics

1 answer:

IrinaK [193]4 years ago

8 0

Answer:

1.98V

Explanation:

V =IR

V =Voltage

I =Current

R = Resistance $V =IR\\V = 100 (0.0198)\\V = 1.98 volts\\Voltage 1.98V$

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A block is being pulled by a rope in a straight line across a horizontal floor which is non frictionless. The rope is pulling on

ikadub [295]

Answer:

60 N

Explanation:

We can answer the question by using Newton's third law, which states that:

"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"

In this situation, we can identify the rope as object A, and the block as object B.

We are told that the rope exerts a force of 60 N on the block: if we apply Newton's third law, therefore, we can say that the block will also exert an equal (60 N) and opposite (in direction) force on the rope.

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3 years ago

A 3.0-kg block starts at rest at the top of a 37° incline, which is 5.0 m long. Its speed when it reaches the bottom is 2.0 m/s.

Mama L [17]

Answer: $f_{r}$ = 16.49N

Explanation: The object is placed on an inclined plane at an angle of 37° thus making it weight have two component,

$W_{x}$ = horizontal component of the weight = mgsinФ

$W_{y}$ = vertical component of weight = mgcosФ

Due to the way the object is positioned, the horizontal component of force will accelerate the object thus acting as an applied force.

by using newton's law of motion, we have that

mgsinФ - $f_{r}$ = ma

where m = mass of object=5kg

a = acceleration= unknown

Ф = angle of inclination = 37°

g = acceleration due to gravity = 9.8 $m/s^{2}$

$f_{r}$ = frictional force = unknown

we need to first get the acceleration before the frictional force which is gotten by using the equation below

$v^{2} = u^{2} + 2aS$

where v = final velocity = 2m/s

u = initial velocity = 0m/s (because the object started from rest)

a= unknown

S= distance covered = length of plane = 5m

$2^{2} = 0^{2} + 2*a*5\\\\4= 10 *a\\\\a = \frac{4}{10} \\a = 0.4m/s^{2}$

we slot in a into the equation below to get frictional force

mgsinФ - $f_{r}$ = ma

3 * 9.8 * sin 37 - $f_{r}$ = 3* 0.4

17.9633 - $f_{r}$ = 1.2

$f_{r}$ = 17.9633 - 1.2

$f_{r}$ = 16.49N

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4 years ago

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bearhunter [10]

Answer:

Colour

Malleability

Ductility

Lustre

Conductivity

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Explanation:

Color : Silver-White.

Malleability : Capable of being shaped or bent.

Ductility : Easily pulled or stretched into a thin wire.

Luster : Has a shine or glow.

Conductivity : Good transmission of heat or electricity.

Softness : Soft enough to be cut with a knife.

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The answer would be B.

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