A converging lens can produce both real and virtual images depending on the position of the object. Explain when converging lens
es can produce virtual images and describe the image produced.
A) A virtual image is produced if the object is on the focal point, the image is upright, enlarged and on the same side of the lens as the object.
B) A virtual image is produced if the object is on the focal point, the image is inverted, enlarged and on the opposite side of the lens from the object.
C) A virtual image is produced if the object is between the focal point and the lens, the image will be upright, enlarged and on the same side of the lens
as the object.
D) A virtual image is produced if the object is between the focal point and the
lens, the image will be upright, reduced and on the opposite side of the
lens from the object.
A) A virtual image is produced if the object is on the focal point, the image is upright, enlarged and on the same side of the lens as the object.
B) A virtual image is produced if the object is on the focal point, the image is inverted, enlarged and on the opposite side of the lens from the object.
C) A virtual image is produced if the object is between the focal point and the lens, the image will be upright, enlarged and on the same side of the lens
as the object.
D) A virtual image is produced if the object is between the focal point and the
lens, the image will be upright, reduced and on the opposite side of the
lens from the object.
2 answers:
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Answer:
KE = 1.75 J
Explanation:
given,
mass of ball, m₁ = 300 g = 0.3 Kg
mass of ball 2, m₂ = 600 g = 0.6 Kg
length of the rod = 40 cm = 0.4 m
Angular speed = 100 rpm=
=10.47\ rad/s
now, finding the position of center of mass of the system
r₁ + r₂ = 0.4 m.....(1)
equating momentum about center of mass
m₁r₁ = m₂ r₂
0.3 x r₁ = 0.6 r₂
r₁ = 2 r₂
Putting value in equation 1
2 r₂ + r₂ = 0.4
r₂ = 0.4/3
r₁ = 0.8/3
now, calculation of rotational energy
KE = 1.75 J
the rotational kinetic energy is equal to 1.75 J
