Answer:
Explanation:
A tug of war is game where two teams will be pulling a rope horizontally,
So,
Given that,
You applied a force of F1 = 50N
You friend you are pulling against applied a force of F2 = 40N
A. Tension on the rope.
Let the tension on the rope be T
The tension cause by you on the rope is the force you applied
T = 50N.
The tension cause by your friend is also
T = 40N
Adding the two tension together
T+T = 50+40
2T = 90
T = 45
OR you will see the rope as a pulley system, i.e. we will assume that the two friend force cause a tension on the rope, their are two tension on the rope, and two forces are applied
Then, tension is equal to force applied
T+T = 40+50
2T = 90
T = 45N
b. Net force by you
In this case we will take your position as the positive direction, I.e. the net force cause by you
Using newton second law
Fnet. = ΣFx
Fnet = F1—F2
Fnet = 50—40
Fnet = 10 N
c. Fnet by your friend
In this case we will take your friends position as the positive direction, I.e. the net force cause by your friend.
Fnet. = ΣFx
Fnet = F2—F1
Fnet = 40—50
Fnet = —10 N
